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saveliy_v [14]
2 years ago
11

PLZ PLZ WITH EXPLANATION

Mathematics
1 answer:
Vadim26 [7]2 years ago
8 0

Answer:

For the first 2 pages, you will want to count how many sides and angles for the stated figure above. Then you want to figure out what other figures that are related to the figure stated above. i.e. a square is a rectangle but not all rectangles are squares. On the last page you want to figure out what is the figure's name and other names that are related/same on the figure's original name. And lastly for part II you want to do the same thing for page 1 and 2, but instead you want to compare and contrast the 2 figures stated above. i.e. Parallelograms and Trapezoids.

Step-by-step explanation:

Hope this helps! :)

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15 feet is the answer
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Find the scale factor of the smaller figure to the larger figure
guapka [62]

Answer:

#9: 1.2

#10: 1.25

Step-by-step explanation:

To find the scale factor of the smaller figure to the larger figure, we're going to be dividing the measurements of corresponding edges.

\frac{larger figure}{smaller figure}

If you wanted to find the scale factor of the larger figure to the smaller figure, you'd do: \frac{smaller figure}{larger figure}

Question #9:

Left edges: \frac{larger figure}{smaller figure} ⇒ \frac{24}{20} = 1.2

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{25} = 1.2

<em>(You should get the same number as long as the figures are similar.)</em>

<em />

Question #10:

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{24} = 1.25

<em>(There are no corresponding edges with measurements that we can compare.)</em>

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~Hope this helps!~

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3 years ago
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Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join
zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx  = 1

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y)  and replacing a and b with their respective values, we have

\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx  = 1

Since c is a constant, we can bring it out of the integral sign; to give us

c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx  = 1

Open the bracket

c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

Integrate with respect to y

c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

Substitute 0 and 3 for y

c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

c\int\limits^3_0 {(\frac{x* 9}{2}  +\frac{x * 27}{3} ) - (0  +0) \, dx = 1

c\int\limits^3_0 {(\frac{9x}{2}  +\frac{27x}{3} )  \, dx = 1

Add fraction

c\int\limits^3_0 {(\frac{27x + 54x}{6})  \, dx = 1

c\int\limits^3_0 {\frac{81x}{6}  \, dx = 1

Rewrite;

c\int\limits^3_0 (81x * \frac{1}{6})  \, dx = 1

The \frac{1}{6} is a constant, so it can be removed from the integral sign to give

c * \frac{1}{6}\int\limits^3_0 (81x )  \, dx = 1

\frac{c}{6}\int\limits^3_0 (81x )  \, dx = 1

Integrate with respect to x

\frac{c}{6} *  \frac{81x^{2}}{2}   (0,3)  = 1

Substitute 0 and 3 for x

\frac{c}{6} *  \frac{81 * 3^{2} - 81 * 0^{2}}{2}    = 1

\frac{c}{6} *  \frac{81 * 9 - 0}{2}    = 1

\frac{c}{6} *  \frac{729}{2}    = 1

\frac{729c}{12}    = 1

Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

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3 years ago
S=3.2yd<br> A=square <br><br> Find the area
wlad13 [49]

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3.2 x 4 = 12.6
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