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daser333 [38]
3 years ago
6

Ralph notice that there were 15 girls and 10 boys in his math class. What is the relationship between the number of boys and gir

ls in Ralphs math class? Write two equivalent ratios
Mathematics
1 answer:
Firdavs [7]3 years ago
7 0
Equivalent ratios are 15:10 and 3:2.
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I am having trouble with this question. ​
a_sh-v [17]

Answer:

x=12√2

y=45°

Step-by-step explanation:

as we know diagonal of a square

=a√2

=12√2

and

y=45°

8 0
3 years ago
A) 2-x,when x=5
MrRissso [65]

Answer:

a) 2-5 = -3

b) 3(4) + 2(4) = 20

c) (3(5)+2)(5-4) = 17

Step-by-step explanation:

Substitute the variables for their values and then solve from there. Hopefully this helps, I don't know if I answered your question fully.

7 0
3 years ago
Read 2 more answers
Idek how to explain this but please help me
Leno4ka [110]

Answer:

Put 4 in the place of x then you'll get

\frac{10}{22}

3 0
3 years ago
Read 2 more answers
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
a bag contains 5 red marbles,6 green marbles,and 3 blue marbles.if cymra draws a marble ,puts it back and then draws another mar
Ksenya-84 [330]
No of red marbles = 5

Total number of marbles =14


By using probability formula,

P(E)= Number of favorable outcome /
Total number of outcomes

P(E)= 5/14




I hope that was useful ☻
7 0
4 years ago
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