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tatuchka [14]
3 years ago
10

How to use Da Vinci flying pedulum clock

Physics
1 answer:
schepotkina [342]3 years ago
8 0
Da Vinci was fascinated by how timepieces operate. Based on one of his sketches, it uses the laws of motion and a vertical "flying" pendulum escapement to keep accurate time.
The pendulum's weights, in a bucket suspended from a crane-style arm, act as the clock's power source. The weights propel the pendulum from vertical post to vertical post. As it "flies" it turns precision gears, which in turn keep time. To speed up or slow the clock, adjust the weight-balance of the pendulum by adding or removing weights.
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PLEASE PLEASE HELP ME!
Vlad1618 [11]
B: heat is transferred as thermal energy by the interaction of moving particles
6 0
3 years ago
Two trains, each having a speed of 28 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h fli
Semenov [28]

Answer:

The value is D =  70.71 \ km

Explanation:

From the question we are told that

The speed of each train is v =  28 \  km/h

The speed of the bird is v_1 =  60 \  km/h

The distance between the trains is d =  66 \  km

Generally the time taken before the collision occurs is mathematically represented as

t =  \frac{d}{2 * v}

=> t =  \frac{66 }{2 *  28}

=> t = 1.18 \  h

The total distance covered by the bird is mathematically represented as

D =  v_1 *  t

=>   D =  60 * 1.18

=>   D =  70.71 \ km

7 0
3 years ago
The net force on an object moving with constant speed in circular motion is in which direction
ipn [44]

Answer:

the net force is the same direction as the acceleration

Explanation:

so toward the center of the circle about which the object is constantly moving.

7 0
3 years ago
The theory that light exists in quantized "chunks" was proposed in response
Dafna1 [17]
Its D because of the emission spectra
8 0
3 years ago
Read 2 more answers
Consider a simple but surprisingly accurate model for the hydrogen molecule: two positive point charges, each having charge e, a
lyudmila [28]

Answer:

a = R/2

Explanation:

Let R be the radius of the sphere and q = -2e be the charge in it. Let q₁ be the charge at radius a where the one of the point positive charges e is located. . Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πa³

q₁ = q(a/R)³ = -2e(a/R)³. The electric force due to q₁ at r is F₁ = kq₁q/a² = kq²(a/R)³/a² = k(-2e)²a/R³ = 4ke²a/R³.

Let h be the distance between the two point charges. The electric force due to the one point charge on the other is F₂ = ke²/h²

If the net force on either charge is zero, then

F₁ = F₂

4ke²a/R³ = ke²/h²

a = R³/4h²

Since h = 2a, since the charges are equidistant from each other,

a = R³/4(2a)² = R³/8a²

a = R³/8a²

a³ = R³/8

a = ∛(R³/8)

a = R/2

7 0
3 years ago
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