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ira [324]
3 years ago
9

A very long straight current-carrying wire produces a magnetic field of 25 µT at a distance d from the wire. How far will the ma

gnetic field due to this wire be 2.8 µT.
Physics
1 answer:
daser333 [38]3 years ago
6 0

The magnetic field strength of a very long current-carrying wire is proportional to the inverse of the distance from the wire. The farther you go from the wire, the weaker the magnetic field becomes.

B ∝ 1/d

B = magnetic field strength, d = distance from wire

Calculate the scaling factor for d required to change B from 25μT to 2.8μT:

2.8μT/25μT = 1/k

k = 8.9

You must go to a distance of 8.9d to observe a magnetic field strength of 2.8μT

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ohaa [14]

Answer

given,

Assume radius of the disk be = 0.8 m

angular velocity of disk

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magnitude of velocity and acceleration = ?

At the instant of time, t = 0.5 s

ω = ( 5 x (0.5)² + 2 ) r a d / s

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a_t =5 \times 0.8

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normal acceleration

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a_n = 3.25^2\times 0.8

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3 years ago
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3 years ago
a specimen of oil having an initial volume of 5000cm³ is subjected to a pressure of 10⁴N/m² and the volume decreases by 0.20cm³.
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Answer:

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Explanation:

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The negative fate is for the module to be positive since the volume change is negative

       

It is not necessary to reduce the volumes to the SI system, since they are both in the same units

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