A segment of wire carries a current of 25 A along the x axis from x = −2.0 m to x = 0 and then along the y axis from y = 0 to y
= 3.0 m. In this region of space, the magnetic field is equal to 40 mT in the positive z direction. What is the magnitude of the force on this segment of wire?
1 answer:
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The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>
Why?
Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.
We can calculate the vertical force using the following formula:
Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>
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Answer:
The angle between the blue beam and the red beam in the acrylic block is
Explanation:
From the question we are told that
The refractive index of the transparent acrylic plastic for blue light is
The wavelength of the blue light is
The refractive index of the transparent acrylic plastic for red light is
The wavelength of the red light is
The incidence angle is
Generally from Snell's law the angle of refraction of the blue light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
The angle between the blue beam and the red beam in the acrylic block
substituting values