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amm1812
3 years ago
10

In addition to 1 m = 39.37 in, the following exact conversion equivalents are

Physics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

3.76 m/s.

Explanation:

Velocity in mile per hour (mph) = 8.4 miles per hour

Velocity in metre per second (m/s) =?

Next, we shall convert 8.4 mph to ft/h. This can be obtained as follow :

1 mph = 5280 ft/h

Therefore,

8.4 mph = 8.4 mph / 1 mph × 5280 ft/h

8.4 mph = 44352 ft/h

Next, we shall convert 44352 ft/h to in/h. This is illustrated below:

1 ft/h = 12 in/h

Therefore,

44352 ft/h = 44352 ft/h / 1 ft/h × 12 in/h

44352 ft/h = 532224 in/h

Next, we shall convert 532224 in/h to m/h. This can be obtained as follow:

39.37 in/h = 1 m/h

Therefore,

532224 in/h = 532224 in/h / 39.37 in/h × 1 m/h

532224 in/h = 13518.51664 m/h

Next, we shall convert 13518.51664 m/h to m/min. This is illustrated below:

1 m/h = 1/60 m/min

Therefore,

13518.51664 m/h = 13518.51664 m/h / 1 m/h × 1/60 m/min

13518.51664 m/h = 225.30861 m/min

Finally, we shall convert 225.30861 m/min to m/s. This is illustrated below:

1 m/min = 1/60 m/s

Therefore,

225.30861 m/min = 225.30861 m/min / 1 m/min × 1/60 m/s

225.30861 m/min = 3.76 m/s

Therefore,

8.4 miles per hour is equivalent to 3.76 m/s.

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-. A 2kg cart moving to the right at 5m/s collides with an 8kg cart at rest. As a
bulgar [2K]

Answer:

<em>The velocity of the carts after the event is 1 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2+...+m_nv_n

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

Since the total momentum is conserved, then:

P = P'

In a system of two masses, the equation simplifies to:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The common velocity after this situation is:

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

The m1=2 kg cart is moving to the right at v1=5 m/s. It collides with an m2= 8 kg cart at rest (v2=0). Knowing they stick together after the collision, the common speed is:

\displaystyle v'=\frac{2*5+8*0}{2+8}=\frac{10}{10}=1

The velocity of the carts after the event is 1 m/s

3 0
2 years ago
You are attempting to row across a stream in your rowboat. Your paddling speed relative to still water is 3.0 m/s (i.e., if you
Nataliya [291]

Answer:

Please check the attached file for the diagram

Explanation:

The velocity of the of the rowboat V_{tot}  through the river is the resultant velocity. It is obtained taking a vector sum of the velocity in still water and the velocity of the river.

There are several ways to take this vector sum, but the question makes it simple for us to use Pythagoras's theorem because the East and North directions are perpendicular to each other.

Hence;

V_{tot}^2=V_{still}^2+V_{w}^2\\V_{tot}^2=3^2+4^2

V_{tot}=\sqrt{3^2+4^2}\\ V_{tot}=\sqrt{25}=5m/s

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