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strojnjashka [21]
3 years ago
15

Help????? urgent!!!!!!!!

Mathematics
1 answer:
defon3 years ago
3 0
Y=2x-3.
Answer B.

Proof

When y=1 then x=2
y=2x-3
1=2*2-3
1=4-3
1=1

.............
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1/5 divided by 3 is what
Vsevolod [243]

Answer:

the answer would be 1/15, or approximately 0.067.

Step-by-step explanation:

8 0
3 years ago
BRO PLEASE HELP ASAP
KiRa [710]

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bro i think its 10

Step-by-step explanation:

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3 years ago
In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (
DENIUS [597]

Answer:

  • a) T is not homogeneous
  • b) T is not additive
  • c) T is not homogeneous
  • d) T is not additive
  • e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

  • a) T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0). These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).
  • b) T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5). Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).
  • c) T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0) so T is not homogeneous.
  • d) T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0) then T is not additive.
  • e) T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0) then T is not additive.
8 0
3 years ago
0.006 0.06 0.6 6 then
Yuri [45]

60, 600, 6000 etc.


Hope it helps ❤️


Please mark brainliest


❤️

8 0
3 years ago
Find the perimeter of a triangle with sides of 2, 3, and 10 feet.
NISA [10]

Answer:

15 feet

Step-by-step explanation:

the perimeter is the total length of the outside of a shape. 2+3+10=15

3 0
3 years ago
Read 2 more answers
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