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balu736 [363]
3 years ago
15

According to the law of conservation of mass, what should the product side of this single replacement reaction look like? A. H2

ZnCl2 B. H2 + Zn + Cl2 C. H2 + ZnCl2 D. ZnCl2
Chemistry
1 answer:
Katyanochek1 [597]3 years ago
8 0

<u>Answer:</u> The product side must be ZnCl_2+H_2

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive metal displaces a less reactive metal from its chemical reaction.

AB+C\rightarrow CB+A

Metal C is more reactive than metal A.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

When zinc metal reacts with hydrochloric acid, it leads to the production of zinc chloride and hydrogen gas. The chemical reaction follows:

Zn+2HCl\rightarrow ZnCl_2+H_2

<u>On reactant side:</u>

Number of zinc atoms = 1

Number of hydrogen atoms = 2

Number of chlorine atoms = 2

<u>On product side:</u>

Number of zinc atoms = 1

Number of hydrogen atoms = 2

Number of chlorine atoms = 2

Hence, the product side must be ZnCl_2+H_2

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When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.
Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

\Delta T=32.3-25.0\ ^0C=7.3\ ^0C

So,  

\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J

Also, 1 J = 0.001 kJ

So,  

\Delta H=0.03189\ kJ

Also, Molar mass of CaO = 56.0774 g/mol

Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol

Thus, Enthalpy change in kJ/mol is:-

\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol

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3 years ago
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz
zaharov [31]
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E=(3.55X10^17)(6.626X10^-34)
E=2.35223X10^-16

Not sure how many significant figures you needed. Hope this helped.


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