Click on the molecules that represent transpiration.

1 answer:

8 0

Transpiration is the progression of water inside a plant! So, the molecule representing transpiration is going to be good ol' H2O! =)

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What trend would you predict for the next ten years for each region?

Artemon [7]

The new trend will probably be the technology that's in that certain year. Like the trend in the modern days are all electronics or will have to do with electronics. Hope this helps! :) Pls mark me as the BRAINLIEST!!!

3 0

3 years ago

He molecular formula mass of this compound is 180 amu . what are the subscripts in the actual molecular formula?

mezya [45]

I can't actually answer this one if the empirical formula is not given. Luckily, I've found a similar problem from another website. The problem is shown in the picture attached. It shows that the empirical formula is CH₂O. Let's calculate the molar mass of the empirical formula.

Molar mass of E.F = 12 + 2(1) + 16 = 30 g/mol

Then, let's divide this to the molar mass of the molecular formula.
Molar mass of M.F/Molar mass of E.F = 180/30 = 6

Therefore, let's multiply 6 to each subscript in the empirical formula to determine the actual molecular formula.
Actual molecular formula = C₆H₁₂O₆

5 0

3 years ago

Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.

Naddik [55]

Answer:

M Na2SO4 sln = 0.8448 M

Explanation:

molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

⇒ mol Na2SO4 = (3.00 g)*(mol/142.04 g) = 0.02112 mol

⇒ M Na2SO4 sln = (0.02112 mol/0.025 L ) = 0.8448 M

3 0

3 years ago

How might a titration be different if a.1m base solution that produces 2 moles of hydroxide g?

Romashka [77]

Use higher concentration of acid to produce 2 moles of hydrogen to form water

4 0

3 years ago

A gas occupies 1.00 L at standard temperature. What is the volume at 333.0°C?

AURORKA [14]

We use Charles's Law: V1/T1=V2/T2

Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K

Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L

Hope this would help :))

7 0

3 years ago