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2 years ago

Is fireworks a physical or a chemical change and why??

Chemistry

1 answer:

Elanso [62]2 years ago

7 0

Answer:

fireworks is a chemical change

Explanation:

Because during a chemical change, substances are changed into different substances. In different terms, the composition of the substance changes.

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Find the mass of each of these substances? 2.40 mol NaOH

damaskus [11]

Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

4 0

3 years ago

an unknown sample with a mass of 50.0 grams changes from an initial temperature of 22.5°C to a final temperature of 32.4°C. It i

makvit [3.9K]

Answer:

Aluminum

Explanation:

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3 years ago

Evaluate this statement: Substances are made of two or more types of elements.

wolverine [178]

A MOLECULE IS MADE OF TWO OR MORE ELEMENTS CHEMICALLY COMBINED IS KNOWN AS A COMPUND.

A MOLECULE IS MADE OF TWO ATOMS IS JUST AN ELEMENT.

A MOLECULE MADE OF TWO OR MORE ELEMENTS IS KNOWN AS A COMPUND.

6 0

3 years ago

17. A balloon contains 4.50 X 1022 atoms of helium gas. Calculate the mass of helium in<br> grams.

Rashid [163]

Answer:

1.08 grams

Explanation:

first, we need to find the number of moles

we divide 12.1/22.4=0.54 moles

we multiply the number of moles with the molecular mass 0.54x2=1.08g

4 0

3 years ago

Read 2 more answers

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

<u> The final concentration of sodium anion = 0.1035 M</u>

4 0

3 years ago