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2 years ago

Is fireworks a physical or a chemical change and why??

Chemistry

1 answer:

Elanso [62]2 years ago

7 0

Answer:

fireworks is a chemical change

Explanation:

Because during a chemical change, substances are changed into different substances. In different terms, the composition of the substance changes.

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Which of the following does not change the energy of the reactants relative to the activation energy?

creativ13 [48]

Answer:

Adding a catalyst

Explanation:

Activation energy is the minimum amount of energy needed to start a chemical reaction
A Catalyst is a material that increases the rate of a reaction by lowering the activation energy. In other words, a catalyst act to provide an alternative route for the reaction which has a lower activation energy.

6 0

2 years ago

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Ayye yoo who want to answer this question ill give brainlist :)

frez [133]

Answer:

noble-gas notation

Explanation:

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2 years ago

All of the following conditions of STP are true except A. 101.3 kPa B.3.81kPa.L/mol.K C. 24.2 L D. 273.15 K

Tasya [4]

The answer is c 24.2l

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2 years ago

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How much faster does ethane (C2H6) gas travel compared to chlorine gas?

zimovet [89]

Answer:

$\large \boxed{\text{54 $\, \%$ faster }}$

Explanation:

$v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}$

if temperature is constant.

$v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}$

if we are comparing two gases,

$\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ = 70.91 g/mol

M₂ = 30.07 g/mol

Calculation

$\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}$

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2 years ago

Is sugar (C12H22O11) an element or a compound?

Semmy [17]

I believe that sugar is a compound because there are elements that make up sugar

4 0

3 years ago