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ludmilkaskok [199]
3 years ago
12

Your average weekly take home wage is $615. You take a one-week paid vacation and a second week unpaid vacation. You have calcul

ated your total annual expenses to be $31,320 per year. What is your cash surplus at the end of the year??
Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Answer: $45

Step-by-step explanation:

As for the information provided,

The weekly rate of wages = $615

In a year there are 52 weeks, thus annual wages = $615  52 = $31,980

But since one week is an unpaid leaves, there will be no wages for such week.

Accordingly, annual wages shall be reduced by wages of a week = $31,980 - $615 = $31,365

Note: When the leaves are paid leaves wages are earned for such period.

Also the annual expected expenses = $31,320

Therefore, expected surplus at year end = $31,365 - $31,320 = $45

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Which angles intercept a 20 degree arc in a circle? Select all that apply.
marshall27 [118]

Answer:

b. A central angle of 20 degrees

d. An inscribed angle of 10 degrees

Step-by-step explanation:

<u><em>The complete question is</em></u>

Which angles intercept a 20 degree arc in a circle? Select all that apply.

a. A central angle of 10 degrees

b. A central angle of 20 degrees

c. A central angle of 40 degrees

d. An inscribed angle of 10 degrees

e. An inscribed angle of 20 degrees

f. An inscribed angle of 40 degrees

<u><em>Verify each case</em></u>

case a. A central angle of 10 degrees

we know that

<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it'

so

A central angle of 10 degrees, intercept a 10 degree arc in a circle (by central angle)

case b. A central angle of 20 degrees

we know that

<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it'

so

A central angle of 20 degrees, intercept a 20 degree arc in a circle (by central angle)

case c. A central angle of 40 degrees

we know that

<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it'

so

A central angle of 40 degrees, intercept a 40 degree arc in a circle (by central angle)

case d. An inscribed angle of 10 degrees

we know that

The <u><em>inscribed angle</em></u> is half that of the arc it comprises

so

An inscribed angle of 10 degrees, intercept a 20 degree arc in a circle

case e. An inscribed angle of 20 degrees

we know that

The <u><em>inscribed angle</em></u> is half that of the arc it comprises

so

An inscribed angle of 20 degrees, intercept a 40 degree arc in a circle

case f. An inscribed angle of 40 degrees

we know that

The <u><em>inscribed angle</em></u> is half that of the arc it comprises

so

An inscribed angle of 40 degrees, intercept a 80 degree arc in a circle

3 0
3 years ago
Need help with this please​
IceJOKER [234]

Answer:

Step-by-step explanation:

5 0
3 years ago
At lunch, Noah buys two tacos for $2.35 each, chips and salsa for $1.85, and lemonade for $1.60. To pay for his meal, he uses $5
lesya [120]

Answer:

$16.85

Step-by-step explanation:

$2.35(2) + $1.85 + $1.60

$4.70 + $1.85 + $1.60

$6.55 + $1.60

$8.15

- $5.00

$3.15

---------------------------

$20.00

- $3.15

$16.85

7 0
3 years ago
Read 2 more answers
If the angle between each blade of the wind turbine is the same, and each blade has a length of 20 meters, find the distance bet
Ket [755]

A typical windmill has three blades. We can envision these blades in a circle, which a circle = 360 degrees. We want to divide up the angles of the blades so they are even or makes up 360 degrees. We have three blades so we have 3 angles to divide by 360 degrees. So, 360 / 3 = 120 degrees. Now that we know the angle of the blades, we can use the Law of Cos to solve the distance between the blade tip.


Law of Cos

c^2 = a^2 + b^2 - 2(a)(b)(\cos A)


We know

a = 20

b = 20

A = Angle = 120


We need to solve for c

c^2 = a^2 + b^2 - 2(a)(b)(\cos A)


Take the square root of each side of the =

\sqrt{c^2} = \sqrt{a^2 + b^2 - 2(a)(b)(\cos A)}

c = \sqrt{a^2 + b^2 - 2(a)(b)(\cos A)}

Input the values we know into the formula and solve for c:

c = \sqrt{a^2 + b^2 - 2(a)(b)(\cos A)}

c = \sqrt{20^2 + 20^2 - 2(20)(20)(\cos 120)}

c = \sqrt{400 + 400 - 2(20)(20)(\cos 120)}

c = \sqrt{800 - 2(20)(20)(\cos 120)}

c = \sqrt{800 - 2(400)(\cos 120)}

c = \sqrt{800 - 800(\cos 120)}

c = \sqrt{800 - (-400)}

c = \sqrt{1200}

c = 20\sqrt{3}

c = 34.641016

c = 34.64


We now have our answer, which is 34.64 and that is C.






3 0
4 years ago
Kelsey buys several pairs of uniform pants for $17.95 each, and a sweater for $24. Jeana shops at a different store and buys sev
Vitek1552 [10]

Answer:

Options A, C and F are correct

Step-by-step explanation:

The expression in the question has a slight error in it

<em>"17.75x + 24 = 18.95x + 18"</em> is mearnt to be 17.95x + 24 = 18.95x + 18

Options A, C and F is correct

Given the expression  for the situation

17.95x + 24 = 18.95x + 18

collect like terms

17.95x-18.95x=18-24

-x=-6

divide both sides by -1 and solve for x we have

x=6

The girls will both pay the same if they buy six pairs of pants and one sweater.

5 0
3 years ago
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