A boy walks in a circle, traveling a total of 10m, then finishing in the same spot where he started. What is the difference betw
1 answer:
Answer:
<em>The boy had a 0 displacement and traveled a distance of 10 m</em>
Explanation:
<u>Distance and Displacement</u>
Both concepts represent similar and often confusing parameters related to the motion of objects.
The displacement is a vector that measures the change of position an object has when moving. If ro is the initial position and r1 is the final position, then
Note that if both positions are the same, then the displacement can be 0.
The distance is the sum of all distances traveled by the object in its movement, regardless of its initial and final positions.
The question states the boy walks in a circle traveling 10 m in total. It's an indication of the distance traveled.
As indicated above, if the initial and final positions coincide, then the displacement is 0.
Summarizing, the boy had a 0 displacement and traveled a distance of 10 m
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Answer:
a) 3.39 × 10²³ atoms
b) 6.04 × 10⁻²¹ J
c) 1349.35 m/s
Explanation:
Given:
Diameter of the balloon, d = 29.6 cm = 0.296 m
Temperature, T = 19.0° C = 19 + 273 = 292 K
Pressure, P = 1.00 atm = 1.013 × 10⁵ Pa
Volume of the balloon =
or
Volume of the balloon =
or
Volume of the balloon, V = 0.0135 m³
Now,
From the relation,
PV = nRT
where,
n is the number of moles
R is the ideal gas constant = 8.314 kg⋅m²/s²⋅K⋅mol
on substituting the respective values, we get
1.013 × 10⁵ × 0.0135 = n × 8.314 × 292
or
n = 0.563
1 mol = 6.022 × 10²³ atoms
Thus,
0.563 moles will have = 0.563 × 6.022 × 10²³ atoms = 3.39 × 10²³ atoms
b) Average kinetic energy =
where,
Boltzmann constant,
Average kinetic energy =
or
Average kinetic energy = 6.04 × 10⁻²¹ J
c) rms speed =
where, m is the molar mass of the Helium = 0.004 Kg
or
rms speed =
or
rms speed = 1349.35 m/s
Answer:
The portfolio should invest 48.94% in equity while 51.05% in the T-bills.
Explanation:
As the complete question is not given here ,the table of data is missing which is as attached herewith.
From the maximized equation of the utility function it is evident that
For the equity, here as
is percentage of the equity which is to be calculated
is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
is the risk aversion factor which is given as 4.
is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59
By substituting values.
So the weight of equity is 48.94%.
Now the weight of T bills is given as
So the weight of T-bills is 51.05%.
The portfolio should invest 48.94% in equity while 51.05% in the T-bills.
