I think it’s action force please tell me if I’m wrong I hope you have a wonderful day
Answer:
the orbit radius would be divided by 3
Explanation:
In order to orbit the planet, the centripetal force of satellite must balance the gravitational force between planet and satellite.
centripetal Force = Gravitational Force
(Ms)(V)²/r = (G)(Ms)(Mₓ)/r²
V² = GMₓ/r
where,
V = velocity of satellite
G = Gravitational Constant
Mₓ = Mass of Planet
r = orbit radius
but, G = gr²/Mₓ
Therefore,
V² = (Mₓ/r)(gr²/Mₓ)
V = √gr --------------------- equation (1)
where,
g = force of gravity
Now, for change in force of gravity:
V' = √g'r'
where,
g' = 3g
V' = V
Therefore,
V = √3gr' ---------------- equation (2)
Comparing equation (1) and equation (2), we get:
√gr = √3gr'
gr = 3gr'
r = 3r'
r' = r/3
<u>Hence, the orbit radius would be divided by 3.</u>
Two atoms with the same atomic number, but different mass numbers (same number of protons, different number of neutrons), are called isotopes, or isotopic nuclides. Having different numbers of neutrons changes the mass of these atoms, so isotopes have slight variations in their physical and chemical behavior.
Explanation:
Given that,
Initial speed, u = 0
No of rotation is 1 in every 1.2 s
The astronaut is strapped into a seat 4.00 m from the axis, r = 4 m
(a) Let 
is the angular acceleration during the first 40 s. It is given by :
Tangential acceleration is given by :
(b) Let a is the centripetal acceleration. It is given by :
Since, 
Hence, this is the required solution.
The velocity of the parachutist after 4 seconds is 40 m/s (downward)
Explanation:
Before his parachute opens, the man is in free fall, so we can calculate its velocity at time t using the suvat equation:
v = u + at
where
v is the velocity at time t
u is the initial velocity
is the acceleration of gravity (taking downward as positive direction)
Assuming he jumps from rest,
u = 0
So, its velocity after t = 4 s is
And the direction is downward, since the result is positive.
Learn more about free fall:
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