4 years ago

What else would need to be congruent

1 answer:

3 0

If you are going to claim SAS congruence, you need to show the sides on either side of the angle are congruent. One of those sides is AB; the other is AC.

Selection D is appropriate.

You might be interested in

0.6÷1.456 long division

Degger [83]

2.426

Step-by-step explanation:

0 2. 4 2 6

6 1 4. 5 6 0

− 0

1 4

− 1 2

2 5

− 2 4

1 6

− 1 2

4 0

− 3 6

4 0

2 years ago

Read 2 more answers

(Please help I’m really struggling I will give brainliest too :-) for the figure shown on the right, find the value of the varia

bulgar [2K]

Answer:

x = 40

m∠Q = 105°

m∠R = 40°

m∠P = 35°

Step-by-step explanation:

Sum of Angles in a Triangle: 180°

Step 1: Define variables

m∠Q = 2x + 25

m∠R = x

m∠P = x - 5

Step 2: Set up equation

m∠Q + m∠R + m∠P = 180°

2x + 25 + x + x - 5 = 180°

Step 3: Solve for <em>x</em>

4x + 20 = 180

4x = 160

x = 40

Step 4: Solve for measure angles.

m∠Q = 2x + 25

m∠Q = 2(40) + 25 = 80 + 25 = 105°

m∠R = x

m∠R = 40°

m∠P = x - 5

m∠P = 40 - 5 = 35°

6 0

3 years ago

Use the given functions to find f (g(x)), and give the restrictions on x.

torisob [31]

Answer:

$f(g(x)) = \frac{10x-9}{3 + 3x}$

Step-by-step explanation:

Given

$f(x) = \frac{1}{x} - 3$

$g(x) = \frac{3}{x} + 3$

Required

Find f(g(x))

If: $f(x) = \frac{1}{x} - 3$

Then:

$f(g(x)) = \frac{1}{3/x + 3} -3$

Solve the denominator (take LCM)

$f(g(x)) = \frac{1}{\frac{3+3x}{x}} -3$

$f(g(x)) = \frac{x}{3 + 3x} - 3$

It can be solved further as:

$f(g(x)) = \frac{x-3(3 + 3x)}{3 + 3x}$

$f(g(x)) = \frac{x-9 + 9x}{3 + 3x}$

$f(g(x)) = \frac{10x-9}{3 + 3x}$

4 0

3 years ago

How can Victoria justify Step 3 of her work? Rewrite the expression on the left using the distributive property. Multiply both s

ivolga24 [154]

Rewrite the expression on the left using the distributive property

8 0

4 years ago

Read 2 more answers

Can someone please help me?

andrew11 [14]

Answer:

2/5 so 4/10

THE ANSWER IS A

5 0

4 years ago

Read 2 more answers