<h3>
Answer: -10 and -40</h3>
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Explanation:
a = 200 = first term
d = -30 = common difference
Tn = nth term
Tn = a + d(n-1)
Tn = 200 + (-30)(n-1)
Tn = 200 - 30n + 30
Tn = -30n + 230
Set Tn less than 0 and isolate n
Tn < 0
-30n + 230 < 0
230 < 30n
30n > 230
n > 230/30
n > 7.667 approximately
Rounding up to the nearest whole number gets us 
So Tn starts to turn negative when n = 8
We can see that,
Tn = -30n + 230
T7 = -30*7 + 230
T7 = 20
and
Tn = -30n + 230
T8 = -30*8 + 230
T8 = -10 is the 8th term
and lastly
Tn = -30n + 230
T9 = -30*9 + 230
T9 = -40 is the ninth term
Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.
Answer:
she read 25 pages in 60 minutes
Step-by-step explanation:
Answer:
- table: 14, 16, 18
- equation: P = 2n +12
Step-by-step explanation:
Perimeter values will be ...
rectangles . . . perimeter
1 . . . 14
2 . . . 16
3 . . . 18
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The perimeter of a figure is twice the sum of the length and width. Here, the length is a constant 6. The width is n, the number of rectangles. So, the perimeter is ...
P = 2(6 +n) = 12 +2n
Your equation is ...
P = 2n +12 . . . . . . . . perimeter P of figure with n rectangles.
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<em>Additional comment</em>
You may be expected to write the equation using y and x for the perimeter and the number of rectangles. That would be ...
y = 2x +12 . . . . . . . . . perimeter y of figure with x rectangles
Answer:
9pi
Step-by-step explanation:
circumference is 2(pi)(r) or diameter(pi)