Non proportional you can see by the way the graph is
Answer:
x=3
Step-by-step explanation:
Hello,
The first thing you do is set up your equation, and we are solving for x so we are going to get x by itself on one side of the = sign.
2x/3+1=3 First thing: subtract 1 from BOTH sides.
-1 -1
----------------------
2x/3=2 Multipliy by 3 on both sides
*3 *3
-----------------------
2x=6 Divide by 2 on both sides
/2 /2
-----------------------
x=3
I hope this helped you!!!
Answer:
No
Step-by-step explanation:
Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.
Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't
The ratio of of number of homework papers to number of exit tickets of Mr Rowley and Ms. Alvera are not equivalent.
<h3>Ratio</h3>
A ratio is a number representing a comparison between two named things. It is also the relative magnitudes of two quantities usually expressed as a quotient.
Mr Rowley:
- Homework papers = 16
- Tickets to return = 2
Ratio of number of homework papers to number of exit tickets = 16 : 2
= 16 / 2
= 8 / 1
= 8 : 1
Ms Alvera:
- Homework papers = 64
- Tickets to return = 60
Ratio of number of homework papers to number of exit tickets = 64 : 60
= 64/60
= 16 / 15
= 16 : 15
Therefore, the ratio of of number of homework papers to number of exit tickets of Mr Rowley and Ms. Alvera are not equivalent.
Learn more about ratio:
brainly.com/question/2328454
#SPJ1
Answer:
<u>The number is 296.</u>
Step-by-step explanation:
Let's call "x" to the number we are looking for.
Now, the problem states that "5 more than the quotient of a number and 8 is 42". This means that this number is being divided by 8, it's also being additioned 5 and the final result is 42. Therefore, the expression of this operations on this number is the following:
. Let's solve the equation to find x.
1. Write the expression.

2. Substract 5 from both sides and simplify.

3. Multiply 8 on both sides and simplify.

<u>We have found our number, it's 296!</u>