All categories

3 years ago

If you worked at a job for 9.00/hour, what type of correlation is the number of hours worked and your take-home pay?

Chemistry

1 answer:

WITCHER [35]3 years ago

3 0

Answer:

There is a linear correlation between the number of hours worked and take-home pay. And more exactly, a direct proportionality. $C = 9\cdot t$

Explanation:

From statement we deduce that amount of hours worked ( $t$ ) (Independent variable, measured in hours) is directly proportional to take-home pay ( $C$ ) (dependent, measured in monetary units), since proportionality ratio is constant and, therefore, there exists a linear correlation between both variables. That is:

$C \propto t$

$C = k\cdot t$ (Eq. 1)

Where $k$ is the proportionality ratio, measured in monetary units per hour. If we know that $k = 9\,\frac{m.u.}{h}$ , then the resulting correlation is:

$C = 9\cdot t$

There is a linear correlation between the number of hours worked and take-home pay.

You might be interested in

The basic principle in balancing a chemical equation is to ______. hints

Natalija [7]

Answer: obey the "law of conservation of mass".
_____________________________________

5 0

3 years ago

Read 2 more answers

What is an indication that a lake is healthy?

N76 [4]

Answer:

Explanation:

As bioindicators are the organism that indicate or monitor the health of the environment

7 0

3 years ago

Read 2 more answers

Unit: Chemical Quantities

Vaselesa [24]

Answer:

(See explanation for further details)

Explanation:

1) The quantity of moles of sulfur is:

$n = \frac{1.20\times 10^{24}\,atoms}{6.022\times 10^{23}\,\frac{atoms}{mol} }$

$n = 1.993\,moles$

2) The number of atoms of helium is:

$x = (1.5\,moles)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mole} \right)$

$x = 9.033\times 10^{23}\,atoms$

3) The quantity of moles of carbon monoxide is:

$n = \frac{4.15\times 10^{23}\,molecules}{6.022\times 10^{23}\,\frac{molecules}{mol} }$

$n = 0.689\,moles$

4) The number of molecules of sulfur dioxide is:

$x = (2.25\,moles)\cdot \left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)$

$x = 1.355\times 10^{24}\,molecules$

5) The quantity of moles of sodium chloride is:

$n = \frac{2.4\times 10^{23}\,molecules}{6.022\times 10^{23}\,\frac{molecules}{mol} }$

$n = 0.399\,moles$

6) The number of formula units of magnesium iodide is:

$x = (1.8\,moles)\cdot \left(6.022\times 10^{23}\,\frac{f.u.}{mole} \right)$

$x = 1.084\times 10^{24}\,f.u.$

7) The quantity of moles of potassium permanganate is:

$n = \frac{3.67\times 10^{23}\,f.u.}{6.022\times 10^{23}\,\frac{f.u.}{mol} }$

$n = 1.214\,moles$

8) The number of molecules of carbon tetrachloride is:

$x = (0.25\,moles)\cdot \left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)$

$x = 1.506\times 10^{23}\,molecules$

9) The quantity of moles of aluminium is:

$n = \frac{3.67\times 10^{23}\,atoms}{6.022\times 10^{23}\,\frac{atoms}{mol} }$

$n = 0.609\,moles$

10) The number of molecules of oxygen difluoride is:

$x = (3.52\,moles)\cdot \left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)$

$x = 2.120\times 10^{24}\,molecules$

3 0

3 years ago

HELP ME AGAIN FOR BRAINLIEST

oksano4ka [1.4K]

Answer:

1: C

2: a

3: B

4: D

hope this helps

7 0

3 years ago

What 2 types of rock make up a large majority of the composition of earth crust?

maxonik [38]

Igneous and <span>granite are the rocks.</span>

6 0

3 years ago