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68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se

Mnenie [13.5K]

Answer:

$\boxed{\bf\: The \: park \: sold \boxed{ 34{}} \: child \: tickets.}$

Step-by-step explanation:

Given:

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

To Find:

The Number of child tickets the park sold.

Solution:

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

$\sf \: = \: \cfrac{68}{100} \times 50$

Note:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: Cancel One zero of 50 and one zero of 100,That is:-

$\sf = \cfrac{68}{ 10\cancel0} \times 5 \cancel0$

Results to,

$\sf = \cfrac{68}{10} \times 5$

Step 3: Cancel 5 and 10, That is:-

$\sf = \cfrac{68}{ \cancel{10 }} \times \cancel5$

Results to,

$\sf =\: \cfrac{68}{2} \times 1$

$\sf = \cfrac{68}{2}$

Step 4: Cancel 68 and 2, That is:-

$\sf =\: \cfrac{ \cancel{68}}{ \cancel2}$

Results to,

$\sf = \cfrac{34}{1}$

$\sf = 34$

34 is the result.

Hence,

$\underline{ \rm \: The \: park \: sold \: \bold{ 34 } \: child \: tickets.}$

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0

3 years ago

In a version of the game of roulette, a steel ball is rolled onto a wheel that contains 19 red, 19 black and 2 green slots. If t

trasher [3.6K]

Answer:

The probability is 0.3576

Step-by-step explanation:

The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.

For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773

To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649

The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.

As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576

5 0

3 years ago

Look at this system of equations. 2x +5 =9.5 3x + 5y =10.5 What is the value of x+y

stiv31 [10]

Answer:

x = 2.25 y = 0.75

Step-by-step explanation:

2x = 9.5- 5

2x = 4.5

x = 4.5 ÷ 2

x = 2.25

know we now what is x so in the second one we evaluate x

3(2.25) + 5y = 10.5

6.75 + 5y = 10.5

5y = 10.5- 6.75

5y = 3.75

y = 3.75 ÷ 5

y = 0.75

that's it !

if you want to check your answer you can evaluate x and y so it will be like

2×2.25 + 5

= 4.5 + 5 = 9.5

and

3× 2.25 +5×0.75

= 6.75 + 3.75 = 10.5

6 0

3 years ago

Find 40% of 28. Use a fraction

Schach [20]

=40/100×28
=56÷5
=11and1/5

7 0

3 years ago

!!!URGENT!!!

GenaCL600 [577]

Answer:

r = 0.

Step-by-step explanation:

The slope = (y2 - y1) / (x2 - x1)

So (r - (-3)) / (-4-2) = -1/2

(r + 3) / -6 = -1/2

2(r + 3) = 6

2r + 6 = 6

2r = 6 - 6 = 0

r = 0 (answer).

7 0

3 years ago