Answer: 2 1/3
Explanation:
10 2/6 - 7 5/6
You can make both a fraction by multiplying the denominator by the whole number, and then adding the numerator to that number, and keeping the denominator the same. So, 10*6 = 60 and 60 + 2 = 62 and you keep the denominator as 6, which would make 62/6
7*6 = 42 and 42 + 5 = 47 so 7 5/6 becomes 47/6
10 2/6 is equivalent to 62/6
7 5/6 is equivalent to 47/6
This just makes it easier to look at.
Now you just work through the equation.
62/6 - 47/6 = 15/6
15/6 = 2 3/6 = 2 1/3
Answer: m= 1+3
Step-by-step explanation:
Basic math helps.
This is geometry.
Yes.
if you add a you get b.
hope this helps, anytime.
The range of a function is the set of all possible outputs.
When the quadratic functions are in standard form, they generally look like this:
If a is positive, the function opens up; if it’s negative, the function opens down. In this form, the y-coordinate of the vertex is found by evaluating f(−
). For example, consider this function:
f(x) = 
So we’re gonna do: −b/2a=−8/2(−2)=−8/−4=2
Then, we plug this in:
a is negative, so the range is all real numbers less than or equal to 5.
Learn more about range at
brainly.com/question/2264373
#SPJ4
Answer:
#2) is 25
Step-by-step explanation:
the best way to solve any of theses is in the order of pemdas:
●parentheses
●exponents
●multiplication & division
●addition & subtraction
for example lets do #2
9+ (2^2)(4)
the first parenthesis has exponents so you'd do it first. 2^2 (two two times) is 4
9+(4)(4)
when two parentheses are next to Each other you multiply. 4x4 is 16
9+16
then finally you add
25
use these steps for the rest. just comment if you have any questions
This involves quite a lot of arithmetic to do manually.
The first thing you do is to make the first number in row 2 = to 0.
This is done by R2 = -3/2 R1 + R2
so the matrix becomes
( 2 1 1) ( -3 )
( 0 -13/2 3/2) (1/2 )
(5 -1 2) (-2)
Next step is to make the 5 in row 5 = 0
then the -1 must become zero
You aim for the form
( 1 0 0) (x)
(0 1 0) (y)
(0 0 1) ( z)
x , y and z will be the required solutions.
