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3 years ago

Describe the number and type of roots for the polynomial. (how many real and complex?)

1 answer:

7 0

This is a cubic equation so it will have a total of three roots.
there is only one change of sign so the equation will have one positive real root.
The other 2 roots will be negative and might be real or complex

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The length of a rectangle is 30 inches and the

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Answer:

34.99in

Step-by-step explanation:

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4 years ago

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Pls pls pls help meee plssss

umka21 [38]

Answer:

x = 5 or 1

Step-by-step explanation:

Square both sides to get

x^2 - 6x + 9 = 4 now subtract four from both sides

x^2 -6x+5 = 0 now factor ( or use quadratic formula)

(x-5)(x-1) = 0 so x = 5 or 1

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2 years ago

Can someone help me pls

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Answer:

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3 years ago

PLEASE HELP ASAP AND THANKS Find x

baherus [9]

Answer:

The value of x is 2.

Step-by-step explanation:

First, you have to make the left side into 1 fraction by making the denorminator the same :

$\frac{x}{x - 2} + \frac{1}{5}$

$= \frac{5x}{5(x - 2)} + \frac{x - 2}{5(x - 2)}$

$= \frac{5x + x - 2}{5(x - 2)}$

$= \frac{6x - 2}{5(x - 2)}$

Then you have to do cross multiplication :

$\frac{6x - 2}{5(x - 2)} = \frac{2}{x - 2}$

$(6x - 2)(x - 2) = 5(2)(x - 2)$

$6 {x}^{2} - 12x - 2x + 4 = 10x - 20$

$6 {x}^{2} - 14x + 4 = 10x - 20$

$6 {x}^{2} - 14x + 4 - 10x + 20 = 0$

$6 {x}^{2} - 24x + 24 = 0$

$6( {x}^{2} - 4x + 4) = 0$

${x}^{2} - 4x + 4 = 0$

${x}^{2} - 2x - 2x + 4 = 0$

$x(x - 2) - 2(x - 2) = 0$

$(x - 2)(x - 2) = 0$

$x = 2$

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3 years ago

What are the characteristics of a right isosceles triangle

const2013 [10]

Answer:

It has 2 45 degree angles

Step-by-step explanation:

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