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Ilya [14]
2 years ago
11

What would be an ideal experiment to test how different types of surfaces affect friction?

Physics
1 answer:
qaws [65]2 years ago
6 0
<span>C) Two objects of equal weights placed on a glass surface and a wooden surface.</span>
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The path a star takes during its lifetime depends on
Svetlanka [38]

Answer:

c.) Mass (is the answer)

7 0
3 years ago
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by
Vlad [161]

Answer: D. 5cm

Explanation:

Given the following :

Focal length (f) = - 6.0 cm

Height of object = 15.0cm

Distance of object from mirror (u) = 12.0cm

Height of image produced by the mirror =?

Firstly, we calculate the distance of the image from the mirror.

Using the mirror formula

1/f = 1/u + 1/v

1/v = 1/f - 1/u

1/v = 1/-6 - 1/12

1/v = - 1/6 - 1/12

1/v = (- 2 - 1) / 12

1/v = - 3 / 12

v = 12 / - 3

v = - 4

Using the relation :

(Image height / object height) = (- image distance / object distance)

Image height / 15 = - (-4) / 12

Image height / 15 = 4 / 12

Image height = (15 × 4) / 12

Image height = 60 / 12

Image height = 5cm

6 0
3 years ago
What do u mean by free fall?​
Degger [83]

Answer:

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7 0
2 years ago
WILL NAME BEST ANSWER THE BRAINLIEST (if you answer well)
mylen [45]
The best and most correct answer among the choices provided by the question is third choice. What happened during the set-up was the e<span>xcess protons move from the positive rod to the negative rod.</span> I hope my answer has come to your help. God bless and have a nice day ahead!
7 0
3 years ago
A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t)=
True [87]

Answer:

(a) average velocity = 17.6 m/s

(b) when t = 0, v = 0

    when t = 4, v = 19.2 m/s

    when t = 8, v = 28.8 m/s

(c) after starting from rest, the car will be at rest again in 20 s

Explanation:

Given;

x(t)=bt²−ct³, substitute the given values and the equation will become;

x(t)=3t²−0.1t³

(a)average velocity = total distance / total time

total distance, x(t) = 3t²−0.1t³

x(8) = 3t²−0.1t³

X(8) = 3(8)² - 0.1(8)³

X(8) = 140.8 m

total time = 8 s

average velocity = 140.8 / 8

average velocity = 17.6 m/s

(b) instantaneous velocity = dx / dt

dx / dt = 6t - 0.3t²

when t = 0

v = 0

when t = 4 s

v = 6(4) - 0.3(4²) = 19.2 m/s

when t = 8 s

v = 6(8) - 0.3(8²) = 28.8 m/s

(c) the velocity is zero at dx / dt = 0

6t - 0.3t² = 0

t(6 - 0.3t) = 0

t = 0    or  6 - 0.3t = 0

t = 0     or   0.3t = 6

t = 0      or   t = 6 / 0.3

t= 0       or    t =  20 s

After starting from rest, the car will be at rest again in 20 s

6 0
3 years ago
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