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Sidana [21]
3 years ago
15

-y+31-5y-15 need help with this

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
6 0
-6y+16 would be the answer

iogann1982 [59]3 years ago
4 0
-2 x (3y - 8) would be the answer

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Yu-Xi draws a triangle with two angles measuring 79 degrees and 23 degrees. What is the measure, in degrees, of the third angle?
Scrat [10]

Answer:

78 Degrees

Step-by-step explanation:

8 0
3 years ago
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Solve 2x + 4 &gt; 16<br><br> A. x &gt; 10<br> B. x &lt; 6<br> C. x &lt; 10<br> D. x &gt; 6
Salsk061 [2.6K]

Hey there! :)

2x + 4 > 16

We're simply just trying to get x onto it's own side, so let's get rid of any numbers on the same side of it.

We can start out by subtracting both sides by 4.

2x + 4 - 4 > 16 - 4

Simplify.

2x > 12

Then, divide both sides by 2.

2x ÷ 2 > 12 ÷ 2

Simplify.

x > 6

Therefore, our answer is D. x > 6

~Hope I helped!~

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3 years ago
I need to find the absolute mean of this?
Slav-nsk [51]
Give more detail please this makes zero sense
4 0
3 years ago
Olivia has 680 to spend at a bicycle store for some new gear and biking outfits
stira [4]
What is the question
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3 years ago
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

5 0
3 years ago
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