there are 7 students on a committee. To decide which 3 of these students will attend a conference, 3 names are chosen at random
1 answer:
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X| 1 | 15 | 225 |
y| 4 | ? | 900 |
therefore
[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]
Answer: ? = 60
y| 4 | ? | 900 |
therefore
[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]
Answer: ? = 60
