You can state the qurstion in an other way
how many integers between 1-100 has 3 in their prime compostion or how many many numbers can be written as 3*a where a is any number
the multiplication table of 3 shows that 3*33=99
which means that highest product below 100 is 3*33
so there are 33 numbers that are divisible by three
A ^ 3b ^ -2 / ab ^ -4, a ≠ 0, b ≠ 0
First we rewrite the expression respecting the properties of the exponents.
b ^ -2 = 1 / b ^ 2
1 / b ^ -4 = b ^ 4
We have then:
a ^ 3b ^ -2 / ab ^ -4
a ^ 3b ^ 4 / ab ^ 2
answer:
An expression using positive exponents is
D a^3b^4/ab^2
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Answer:
Step-by-step explanation:
A) this is not enough information to compare the mode.
For example:
{1,1,6,11,11]: mean 6, median 6, mode 1 and 11
{4,4,6,8,8} mean 6, median 6 mode, mode 4 and 8
16 % = 38
(16 × 6 = 96
16 / 4 = 4 so = 38/4 = 9.5)
100% = 38*5 + 9.5
=199.5
