Answer:
Explanation:
<h3>for average velocity we use this formula V Vavg =V1+V2<u>
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<u>2</u></h3>
You've described two (2) axes of motion.
The third one would have been up-and-down.
The question is oversimplified, and pretty sloppy.
Relative to the Earth . . .
The Moon is in an elliptical orbit around us, with a period of
27.32... days, and with the Earth at one focus of the ellipse.
Relative to the Sun . . .
The Moon is in an elliptical orbit around the Sun, with a period
of 365.24... days, and with the Sun at one focus of the ellipse,
and the Moon itself makes little dimples or squiggles in its orbit
on account of the gravitational influence of the nearby Earth.
I'm sorry if that seems complicated. You know that motion is
always relative to something, and the solar system is not simple.
Answer:
Just consider the resistance as water flowing through a pipe. If the pipe is too small in radius (consider thin wire as small pipe) water can’t flow easly. If the pipe is big in radius (consider thick wire as big pipe) water can flow easly. So flowing water through a small pipe for a long distance will inversly affect the normal flow where as flowing water through a big pipe for a small distance will not affect too much the normal flow.
So long & thin wire has high resistance. Short & thick wire has low resistance.
B. A wire that is 2 m long and has a cross-sectional area of 0.066
Answer:
Answer:
1.1 x 10^9 ohm metre
Explanation:
diameter = 1.5 mm
length, l = 5 cm
Potential difference, V = 9 V
current, i = 230 micro Ampere = 230 x 10^-6 A
radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m
Let the resistivity is ρ.
Area of crossection
A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2
Use Ohm's law to find the value of resistance
V = i x R
9 = 230 x 10^-6 x R
R = 39130.4 ohm
Use the formula for the resistance
ρ = 1.1 x 10^9 ohm metre
Explanation:
