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vovikov84 [41]
3 years ago
6

Calculate the power of the eye in D when viewing an object 5.70 m away. (Assume the lens-to-retina distance is 2.00 cm. Enter yo

ur answer to at least one decimal place.)
Physics
1 answer:
Tems11 [23]3 years ago
3 0

Answer:

Power=50.17dioptre

Power=50.17D

Explanation:

P=1/f = 1/d₀ + 1/d₁

Where d₀ = the eye's lens and the object distance= 5.70m=

d₁= the eye's lens and the image distance= 0.02m

f= focal length of the lense of the eye

We know that the object can be viewed clearly by the person ,then image and lens of the eye's distance needs to be equal with the retinal and the eye lens distance and this distance is given as 0.02m

Therefore, we can calculate the power using above formula

P= 1/5.70 + 1/0.02

Power=50.17dioptre

Therefore, the power the eye's is using to see the object from distance is 5.70D

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Explanation:

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F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN

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∵ elastic deformation assumption is valid.

so the answer is

F = 25800 K N            and     S_{y} > σ

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