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3 years ago

-3x+7 x=-2 PLEASE SHOW WORK. Thanks

Mathematics

1 answer:

galben [10]3 years ago

5 0

Answer:

1 :

Step 2 :

Equations which are never true :

2.1 Solve : 2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : 2x+1 = 0

Subtract 1 from both sides of the equation :

2x = -1

Divide both sides of the equation by 2:

x = -1/2 = -0.500

One solution was found :

x = -1/2 = -0.500

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What does the equal

sergejj [24]

Plug it in your y= screen of your graphing calculator and hit 2nd and then graph. it will give u a table of values

7 0

3 years ago

In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.

NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE, so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

5 0

3 years ago

Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu

Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.

From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by $\frac{11000}{2}$

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0

3 years ago

A cab charges $1.75 for the flat fee and $0.25 for each mile. write and solve an inequality to determine how many miles eddie ca

ad-work [718]

The answer is a. $1.75 + $0.25x ≤ $15; x ≤ 53 miles

x - the number of miles
C - the cab charge

A cab charges $1.75 for the flat fee and $0.25 for each mile: C = 1.75 + 0.25x.
Eddie has $15 to spend. So, he cannot spend more than 15 on the cab and the maximum amount he can spend is 15. Therefore:
1.75 + 0.25x ≤ 15

Now, let's solve it:
0.25x ≤ 15 - 1.75
0.25x ≤ 13.25
x ≤ 13.25 / 0.25
x ≤ 53

3 0

3 years ago

Use the equation P(A or B)= P(B)-P(A and B) to find the missing value below.

Anvisha [2.4K]

Answer:

$P(B) = \frac{7}{8}$