The flat-bed trailer carries two 2000-kg beams with the upper beam secured by a cable. The coefficients of static friction betwe
en the two beams and between the lower beam and the bed of the trailer are 0.25 and 0.30, respectively. Knowing that the load does not shift, determine
1. The maximum acceleration of the trailer and the corresponding tension in the cable
2. The maximum deceleration of the trailer.
1. The maximum acceleration of the trailer and the corresponding tension in the cable
2. The maximum deceleration of the trailer.
1 answer:
You might be interested in
Answer:
[012] :
Here x component is zero. That is why this is in y- z plane
[721] :
This is in all three plane .It means it is in space.
[110] :
Here z component is zero.
That is why this is in x -y plane
From the cubic unit directions we can easily understand all given directions [012], [721], [110].
Answer:
Part A:
(-ve sign shows heat is getting out)
Part B:
(Heat getting in)
The value of Q at constant specific heat is approximately 361% in difference with variable specific heat and at constant specific heat Q has opposite direction (going in) than Q which is calculated in Part B from table A-23. So taking constant specific heat is not a good idea and is questionable.
Explanation:
Assumptions:
- Gas is ideal
- System is closed system.
- K.E and P.E is neglected
- Process is polytropic
Since Process is polytropic so
Where n=1.25
Since Process is polytropic :
Now,
We will now calculate mass (m) and Temperature T_2.
Part A:
According to energy balance::
From A-20, C_v for Carbon dioxide at 300 K is 0.657 KJ/Kg.k
(-ve sign shows heat is getting out)
Part B:
From Table A-23:
(By interpolation)
(Heat getting in)
The value of Q at constant specific heat is approximately 361% in difference with variable specific heat and at constant specific heat Q has opposite direction (going in) than Q which is calculated in Part B from table A-23. So taking constant specific heat is not a good idea and is questionable.
Answer:
The pressure that will cause yielding in the tank in the longitudinal direction is 1.7 Mpa
Explanation:
We are dealing with a thin-walled pressure vessel here.
the formula for calculating the hoops stress of this pressure vessel is
longitudinal yield stress =
Thickness = 2/1000 =0.002m
Outside diameter = inside siameter + thickness = 2m + 0.002m= 2.002m
Dm = Mean diameter = Outside diameter - thickness = 2.002 - 0.002 = 2m