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grandymaker [24]
3 years ago
15

In addition to passing an ASE certification test, automotive technicians must have __________ year(s) of on the job training or

__________ year(s) of on the job training and a two-year degree in automotive repair to qualify for certification.
Engineering
1 answer:
Lunna [17]3 years ago
8 0
Two years or one year
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List irreversibilities
natali 33 [55]

Answer:

Some of the irreversibilities are listed below:

  • Plastic deformation of solids
  • Transfer of heat over finite difference of temperature
  • When two fluids are mixed together the process is irreversible
  • Combustion of a gas
  • Current flowing through a finite resistor
  • Diffusion and free compression or expansion of gas
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3 years ago
How many color are in da rainbow​
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Seven colors are in the rainbow haha
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2 years ago
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A flow of 12 m/s passes through a 6 m wide, 2 m deep rectangular channel with a bed slope of 0. 001. If the mean velocity of flo
prohojiy [21]

Answer:

manning's coefficient is 0.0357

Explanation:

Given:

Velocity of flow, v = 12 m/s

Width of the channel, b = 6 m

Depth of the channel, d = 2 m

bed slope, s = 0.001

mean velocity of flow, V = 1 m/s

now, the velocity is given as:

V= \frac{1}{n}R^{\frac{2}{3}}S^{\frac{1}{2}}

where,

n is the manning's coefficient

R is hydraulic mean depth

R = (Area of the channel) / (wetted Perimeter of the channel)

now,

R = (2 × 6) / ((2 × 2) + 6)

or

R = 12 / 10 = 1.2 m

now, on substituting the values in the equation for velocity, we get

1= \frac{1}{n}1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}

or

n= 1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}

or

n = 0.0357

hence, the value of manning's coefficient is 0.0357

8 0
3 years ago
Whats the difference between GeForce GTX 1060 and Geforce GTX 3060? Is there any big changes to FPS and other settings?
ZanzabumX [31]

Answer:

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Explanation:

7 0
3 years ago
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You are working as an electrical technician. One day, out in the field, you need an inductor but cannot find one. Looking in you
telo118 [61]

Answer:

a) the inductance of the coil is 6 mH

b) the emf generated in the coil is 18 mV  

Explanation:

Given the data in the question;

N = 570 turns

diameter of tube d = 8.10 cm = 0.081 m

length of the wire-wrapped portion l =  35.0 cm = 0.35 m

a) the inductance of the coil (in mH)

inductance of solenoid

L = N²μA / l

A = πd²/4  

so

L = N²μ(πd²/4) / l

L = N²μ(πd²) / 4l

we know that μ = 4π × 10⁻⁷ TmA⁻¹

we substitute

L = [(570)² × 4π × 10⁻⁷× ( π × (0.081)² )] / 4(0.35)

L =  0.00841549 / 1.4

L = 6 × 10⁻³ H    

L = 6 × 10⁻³ × 1000 mH

L = 6 mH

Therefore, the inductance of the coil is 6 mH

b)

Emf ( ∈ ) = L di/dt

given that; di/dt = 3.00 A/sec

{∴ di = 3 - 0 = 3 and dt = 1 sec}

Emf ( ∈ ) = L di/dt

we substitute

⇒ 6 × 10⁻³ ( 3/1 )

= 18 × 10⁻³ V

= 18 × 10⁻³ × 1000

= 18 mV  

Therefore, the emf generated in the coil is 18 mV  

7 0
3 years ago
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