<span> |2x − 5| − 2 = 3
</span><span>1) |2x − 5| = 3 +2
2)</span><span> |2x − 5| = 5
3) 2x-5 = 5, or 2x-5= -5
4)2x=10, or 2x=0
5) x = 5 , or x = 0
Check:
</span> |2x − 5| − 2 = 3
|2*5− 5| − 2 = 3 or |2*0 − 5| − 2 = 3
|5|-2=3 or |-5| -2 =3
3=3 (true) or 3=3 (true)
All steps are correct.
The distance between the ground and the kite to the nearest foot is 64 ft.
<h3>What is a right angle triangle?</h3>
A right angle triangle is a triangle that has one of its sides as 90 degrees. The situation forms a right angle triangle.
Hence,
The length of the kite string is the hypotenuse side of the triangle formed.
The height between the ground and the kite is the opposite side of the triangle formed.
Therefore, using trigonometric ratio,
sin 40 = opposite / hypotenuse
sin 40 = h / 100
cross multiply
h = 100 sin 40
h = 100 × 0.64278760968
h = 64.2787609687
h = 64 ft
Therefore, the distance between the ground and the kite to the nearest foot is 64 ft.
learn more on right triangle here: brainly.com/question/27482803
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Answer:
78 sqr units
Step-by-step explanation:
Use the Pythagorean Theorem to help find the base opposite the two.
The base of the second parallel line is sqrt( (15^2) - (12^2) ) = sqrt(81) = 9
The second base = 9 + 2 = 11
Area = (b1 + b2)*h/2
h = 12
b1 = 2
b2 = 11
h = 12
Area = (11 + 2)*12/2
Area = 13 * 12/2
Area = 78 square units
Answer:
c
Step-by-step explanation:
come on ! you can literally see that in the chart.
how many parts of the gray 3/8 are covered by the gray 1/4 ?
2 parts = 2/8 are clearly covered by 1/4.
2/8 is what part of 3/8 ?
it is the same question as "2 is what part of 3" ?
is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.
is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.
is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !
is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.
once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.
Answer:
41/6
Step-by-step explanation:
Take the root of both sides and solve.
