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3 years ago

What is the distance between two consecutive points in phase on a wave called?

Physics

2 answers:

balu736 [363]3 years ago

7 0

The distance between two consecutive points in a wave is called the wavelength.

KiRa [710]3 years ago

3 0

THE WAVE LENGTH IS THE DISTANCE BETWEEN TWO CONSECTIVE POINTS IN A PHASE PN A WAVE

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NEED ANSWER PLEASE!!!!

olganol [36]

Answer:A, Concave

Explanation:

3 0

4 years ago

A composite load consists of three loads connected in parallel. One draws 100 W at a PF of 0.92 lagging, another takes 250 W at

fenix001 [56]

Answer:

a) $I_{RMS} = 4.79 A$

b) $PF = 0.908$

Explanation:

Get the reactive powers for each of the loads:

Reactive power = Real Power * tanθ

For load 1

Active power, P₁ = 100 W

Power factor, $cos \theta_{1} = 0.92$

$\theta_{1} = cos^{-1} 0.92\\\theta_{1} = 23.074$

$Q_{1}= P_{1} tan \theta_{1} \\Q_{1}= 100tan 23.074\\Q_{1}= 42.60 W$

For load 2

Active power, P₂ = 250 W

Power factor, $cos \theta_{2} = 0.8$

$\theta_{2} = cos^{-1} 0.8\\\theta_{2} = 36.87$

$Q_{2}= P_{1} tan \theta_{2} \\Q_{2}= 250tan 36.87\\Q_{2}= 187.5 W$

For load 3

Active power, P₃ = 250 W

Power factor, $cos \theta_{3} = 1$

$\theta_{3} = cos^{-1} 1\\\theta_{3} =0$

$Q_{2}= P_{1} tan \theta_{3} \\Q_{3}= 150tan 0\\Q_{3}= 0 W$

Calculate the total reactive power, $Q_{net} = 42.6 + 187.5 + 0$

$Q_{net} = 230.1 W$

Calculate the total active power, $P_{net} = 100 + 250 + 150 = 500 W$

$S_{net} = P_{net} + Q_{net} \\S_{net} = 500 + j230.1$

$P_{net} = IVcos \theta_{net}$

$\theta_{net} = tan^{-1} \frac{230.1}{500} \\\theta_{net} = 24.712$

V = 115 $V_{rms}$

$500 = I_{RMS} * 115 cos 24.712\\I_{RMS} = 500/104.47\\ I_{RMS} = 4.79 A$

b) Power factor of the composite load is $cos\theta_{net}$

$\theta_{net} = 24.712\\PF = cos 24.712\\PF = 0.908$

4 0

3 years ago

Gwar [14]

Answer:

For 1: The correct option is Option C.

For 3: The final velocity of the opponent is 1m/s

Explanation:

During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$ ...(1)

where,

$m_1,u_1\text{ and }v_1$ are the mass, initial velocity and final velocity of first object

$m_2,u_2\text{ and }v_2$ are the mass, initial velocity and final velocity of second object

For 1:

We are Given:

$m_1=150g=0.15kg\\u_1=?m/s\\v_1=0.85m/s\\m_2=3500g=3.5kg\\u_2=0m/s\\v_2=0.85m/s$

Putting values in equation 1, we get:

$(0.15\times u_1)+(3.5\times 0)=(3.5+0.15)\times 0.85\\\\u_1=20.683\approx 21m/s$

Hence, the correct answer is Option C.

For 2:

Impulse is defined as the product of force applied on an object and time taken by the object.

Mathematically,

$J=F\times t$

where,

F = force applied on the object

t = time taken

J = impulse on that object

Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.

Hence, the impulse remains the same.

For 3:

Let the speed in right direction be positive and left direction be negative.

We are Given:

$m_1=240kg\\u_1=0m/s\\v_1=-1m/s\\m_2=80kg\\u_2=-2m/s\\v_2=?m/s$

Putting values in equation 1, we get:

$(240\times 0)+(80\times (-2))=(240\times (-1))+(80\times v_2)\\\\v_2=1m/s$

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.

4 0

3 years ago

Who were the first two people in the universe? what is faster then the speed of light?

ivanzaharov [21]

Answer:

Adam and Eve are the Bible's first man and first woman. the only thing capable of traveling faster than the speed of light is, somewhat paradoxically, light itself, though only when not in the vacuum of space. Of note, regardless of the medium, light will never exceed its maximum speed of 186,282 miles per second.

Explanation:

5 0

3 years ago

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Consider the incomplete equation below mc020-1.jpg If this equation was completed, which statement would it best support? Nuclea

vagabundo [1.1K]

Nuclear fission produces elements that are heavier than helium.

The elements that are used in nuclear fission and their products are much heavier than helium.

8 0

3 years ago

Read 2 more answers