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inessss [21]
3 years ago
9

This glass of lemonade is sitting in the hot summer sun. As time passes, in which direction will heat transfer take place?

Physics
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

A.

ice → lemonade it is the correct answer of this question

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Compounds are elements that are chemically combined, like water for example (it’s both hydrogen and oxygen.)
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Which of the following is a balanced chemical equation?
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Explanation:e=mwS

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Calculate the speed of the car at each checkpoint by
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Answer: The speed at the first quarter checkpoint is 0.74 m/s. The speed at the second quarter checkpoint is 1.40 m/s. The speed at the third quarter checkpoint is 1.61 m/s. The speed at the finish line is 1.89 m/s.

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3 years ago
Transmission Lines and Health. Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the elec
Blababa [14]

Calculate the magnetic field strength at the ground. Treat the transmission line as infinitely long. The magnetic field strength is then given by:

B = μ₀I/(2πr)

B = magnetic field strength, μ₀ = magnetic constant, I = current, r = distance from line

Given values:

μ₀ = 4π×10⁻⁷H/m, I = 170A, r = 8.0m

Plug in and solve for B:

B = 4π×10⁻⁷(170)/(2π(8.0))

B = 4.25×10⁻⁶T

The earth's magnetic field strength is 0.50G or 5.0×10⁻⁵T. Calculate the ratio of the line's magnetic field strength to earth's magnetic field strength:

4.25×10⁻⁶/(5.0×10⁻⁵)

= 0.085

= 8.5%

The transmission line's magnetic field strength is 8.5% of that of earth's natural magnetic field. This is no cause for worry.

8 0
3 years ago
758 j of heat are added to 0.750 kg of copper. how much does its temperature change?(unit=degrees c) PLEASE HELPPPPPPP MEEEEEE
DiKsa [7]

Answer:

2.6^{\circ}C

Explanation:

When a substance is supplied with a certain amount of heat energy, the temperature of the substance increases according to the equation

Q=mC\Delta T

where

m is the mass of the substance

Q is the amount of energy supplied

C is the specific heat of the substance

\Delta T is the temperature change

In this problem:

Q = 758 J is the energy supplied

m = 0.750 kg is the mass of the sample

C=385 J/kg^{\circ}C is the specific heat of copper

Re-arranging the equation, we can find the increase in temperature:

\Delta T=\frac{Q}{mC}=\frac{758}{(0.750)(385)}=2.6^{\circ}C

5 0
3 years ago
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