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gtnhenbr [62]
4 years ago
13

Solving an Equation for a Given Variable

Mathematics
2 answers:
skelet666 [1.2K]4 years ago
7 0
What nath is this ??????????
Rom4ik [11]4 years ago
6 0
I think it is that a
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Un terreno ha sido cultivado con tres variedades de claveles. La sexta parte ha sido sembrada por
Minchanka [31]

Answer:

1) Se siembra cinco doceavas partes del terreno con claveles rojos y amarillos, 2) Se siembra siete doceavas partes del terreno con claveles blancos.

Step-by-step explanation:

El enunciado se encuentra incompleto. La pregunta faltante es:

2 ¿Qué parte del terreno corresponde a los claveles blancos?

1) Sea A el área total sembrada con los tres tipos de claveles. Entonces, las áreas sembradas con claveles rojos y claveles amarillos son \frac{1}{6}\cdot A y \frac{1}{4} \cdot A, respectivamente.

El área sembrada con claveles rojos y amarillos se obtiene al sumar las áreas correspondientes, es decir:

x = \frac{1}{6}\cdot A + \frac{1}{4}\cdot A

x = \left(\frac{1}{6}+\frac{1}{4}\right)\cdot A

x = \left(\frac{4+6}{24} \right)\cdot A

x = \frac{10}{24}\cdot A

x = \frac{5}{12}\cdot A

Se siembra cinco doceavas partes del terreno con claveles rojos y amarillos.

2) El área sembrada con claveles blancos se obtiene al sustraer el área obtenida en el punto anterior del área total. Esto es:

x = A - \frac{5}{12}\cdot A

x = \left(1-\frac{5}{12} \right)\cdot A

x = \left(\frac{12}{12}-\frac{5}{12}  \right)\cdot A

x = \left(\frac{12-5}{12} \right)\cdot A

x = \frac{7}{12}\cdot A

Se siembra siete doceavas partes del terreno con claveles blancos.

8 0
4 years ago
Please explain and solve
NemiM [27]
Weird question wording. I take it should mean that this is a quadratic equation with solutions of x = -5 and x = 8. Then these are the factors: (x+5) and (x-8).
 So

(x+5)(x-8) = 0 is the equation because x = -5 and x = 8 can make left-side equal to 0. But we expand so it becomes x² - 3x - 40 = 0
6 0
3 years ago
Dominique bikes 1/6 mile every day. How many days will it take her to bike 8 miles?​
Bond [772]
1/6 of a mi - 1 day, 2/6 of a mi- 2 days, 3/6 of a mi- 3 days, 4/6 of a mi- 4 days, 5/6 of a mile - 5 days, 1 mile - 6 days, 1 1/6 mi - 7 days, 1 2/6 mi - 8 days , so on & so forth, do you understand ?
7 0
3 years ago
Read 2 more answers
Find the midpoint of the segment with the following endpoints. (6, 4) and (9,9)
Rina8888 [55]

Answer:

15/2, 13/2.

Step-by-step explanation:

Here's a graph as well.

7 0
3 years ago
Read 2 more answers
Identify the function that contains the data in the following table: x     -2         0         2         3         5     f(x)  
Veseljchak [2.6K]

Answer:

f(x) = |x - 2| + 1

Step-by-step explanation:

When x = -2, then f(-2) = 5

The first function gives the relation equation as f(x) = |x| + 1

So, f(-2) = |-2| + 1 = 2 + 1 = 3 ≠ 5

{Since the definition of |x| is given by  

|x| = x, when x ≥ 0 and |x| = - x, when x < 0}

Again, the second  function gives the relation equation as f(x) = |x - 2|.

So, f(-2) = |-2 - 2| = |-4| = 4 ≠ 5

Now, the third function gives the relation equation as f(x) = |x - 2| - 1.

So, f(-2) = |-2 - 2| - 1 = |-4| - 1 = 4 - 1 = 3 ≠5

Again, the fourth function gives the relation equation as f(x) = |x - 2| + 1.

Hence, f(-2) = |-2 - 2| + 1 = |-4| + 1 = 4 + 1 = 5  

Therefore, the fourth function f(x) = |x - 2| + 1 contains the given data table.  

For further clarity we can check f(0) = 3, f(2) = 1, f(3) = 2 and f(5) = 4. (Answer)

6 0
4 years ago
Read 2 more answers
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