Question

A solenoid contains 705 coils of very thin wire evenly wrapped over a length of 15.5 cm. Each coil is 2.50 cm in diameter. If this solenoid carries a current of 6.5 A, what is the magnetic field at its center?

Answer 1

Answer:

The magnetic field at its center is 0.037 T.

Explanation:

Given that,

Number of coil = 705

Length = 15.5 cm

Diameter = 2.50 cm

Current = 6.5 A

We need to calculate the  magnetic field at its center of solenoid

Using formula of magnetic field

$B= \dfrac{\mu NI}{L}$

Where, I = current

L = length

N = number of coil

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times705\times6.5}{15.5\times10^{-2}}$

$B=0.037\ T$

Hence, The magnetic field at its center is 0.037 T.