I’m in the middle of a test right now. If anybody knows this can they help
1 answer:
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Answer:
t = 4.0 min
Explanation:
given data:
diameter of rod = 2 cm
T_1 = 100 degree celcius
Air stream temperature = 20 degree celcius
heat transfer coefficient = 200 W/m2. K
WE KNOW THAT
copper thermal conductivity = k = 401 W/m °C
copper specific heat Cp = 385 J/kg.°C
density of copper = 8933 kg/m3
charateristic length is given as Lc
Biot number is given as
Bi = 0.0025
As Bi is greater than 0.1 therefore lumped system analysis is applicable
so we have
............1
where b is given as
b = 0.01163 s^{-1}
putting value in equation 1
solving for t we get
t = 4.0 min
Answer : The partial pressure of is, 67.009 atm
Solution : Given,
Partial pressure of at equilibrium = 30.6 atm
Partial pressure of at equilibrium = 13.9 atm
Equilibrium constant =
The given balanced equilibrium reaction is,
The expression of will be,
Now put all the values of partial pressure, we get
Therefore, the partial pressure of is, 67.009 atm