I’m in the middle of a test right now. If anybody knows this can they help
1 answer:
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Answer:
The same as the escape velocity of asteorid A (50m/s)
Explanation:
The escape velocity is described as follows:
where is the universal gravitational constant,
is the mass of the asteroid and
is the radius
and since the scape velocity is 50m/s:
Now, if the astroid B has twice mass and twice the radius, we have that tha mass is:
and the radius is:
inserting these values into the formula for escape velocity:
and we have found that , so the two asteroids have the same escape velocity.
We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.
The answer is
Asteroid B would have an escape velocity the same as the escape velocity of asteroid A
Their velocity afterward is v=3.467 m/s
Explanation:
Given:
Mass of the first football player= 91.5 kg
Initial velocity of the football player 3.73 m/s
Mass of second football player=63.56 kg
Initial velocity of the second football player=3.09 m/s
To find:
Final velocity of both players=?
Solution:
According to the law of conservation of momentum,
Initial momentum =final momentum
mathematically represented as
...........................(1)
where
=intial velocity of the football player
= inital velocity of second football player
=finall velocity of the first football player
=final velocity of second football player
after tackling , both the football players moves with the same velocity,
so
Hence equation (1) becomes
now substituting the values,
v=3.467 m/s