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3 years ago

What is the current flowing through a 10 resistor in a parallel circuit with a 120 V potential difference across it?

Physics

2 answers:

Elena L [17]3 years ago

5 0

Answer:

let current flow be x

Explanation:

than we know potential difference = energy supply / charge then 120 = 10 /x then x=12 therefore pd = 12 v

taurus [48]3 years ago

4 0

120=10/X
12=1/X
12•1=12
So the answer is 12
Hope this helps can u make me branliest please ❤️

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A charge of 40 pC is distributed on an isolated spherical conductor that has a 4.0-cm radius. Point A is 1.0 cm from the center

Hitman42 [59]

Answer:

Given that the charge on the conductor is Q=40 x 10-12 C

radius is r=0.04m

the potential at an inner point is constant and is same as that on the sphere that is

Va=kQ/r

=9 x 109 x40 x 10-12 /0.04

=9V

the potential at a point R=0.05m is

Vb=kQ/R

=9 x 109 x40 x 10-12 /0.05

=7.2V

Hence the potential difference is Va-Vb=1.8V

Explanation:

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3 years ago

A particle moves in the xy plane, starting from the origin at t=0 with initial velocity having an x component of 20 m/s and a y

777dan777 [17]

Answer:

a. $\vec{v} = \vec{v_x} + \vec{v_y} = (20 + 4t)\hat{x} - 15 \hat{y}$

b. 25m/s

Explanation:

Let t be the time.

The velocity in the x direction that is subjected to acceleration of 4 m/s2

$v_x = 20 + 4t$ m/s

The velocity in the y direction

$v_y = -15$ m/s

The total velocity at any time, which is the combination of both x and y vectors of velocity

$\vec{v} = \vec{v_x} + \vec{v_y} = (20 + 4t)\hat{x} - 15 \hat{y}$

b) at t = 5

$v^2 = v_x^2 + v_y^2 = (20 + 4t)^2 + 15^2 = (20 + 4*5)^2 + 15^2 = 400^2 + 225 = 625$

$v = \sqrt{625} = 25 m/s$

5 0

3 years ago

What does B represent?

jenyasd209 [6]

B is a trough.

A trough is the opposite of a crest, in that it occurs at the maximum negative displacement of a wave.

In this problem, A would be the crest, C would be the wavelength, and D would be the amplitude.

Hope this helps!! :)

5 0

3 years ago

You calibrated a different pipet and determined its volume to be 25.40 mL. You then use it to determine the density of an unknow

just olya [345]

Answer:

1148.37401575 kg/m³

Explanation:

Volume of liquid in pipet

25.4 mL

Mass of liquid

$77.8760-48.7073=29.1687\ g$

Density is given by

$\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{29.1687}{25.4}\\\Rightarrow \rho=1.14837401575\ g/ml=1.14837401575\times 10^3=1148.37401575\ kg/m^3$

The density of the unknown liquid is 1148.37401575 kg/m³

4 0

3 years ago

A hand pushes two blocks, A and B, along a frictionless table for a distance d. When the hand starts to push, the blocks are mov

Kitty [74]

<span>net work = change in kinetic energy

for Block B, we just have the force from block A acting on it
F(ab)d= .5(1)vf² - .5(1)(2²)
F(ab)d= .5vf² - 2

Block A, we have the force from the hand going in one direction and the force of block B on A going the opposite direction

10-F(ba)d = .5(4)vf² - .5(4)(2²)
10-F(ba)d = 2vf² - 8
F(ba)d = 18 - 2vf²

now we have two equations:
F(ba)d = 18 - 2vf²
F(ab)d= .5vf² - 2

since the magnitude of F(ba) and F(ab) is the same, substitute and find vf (I already took into account the direction when solving for F(ab)

10-.5vf² + 2 = 2vf² - 8
12 - .5vf² = 2vf² - 8
20 = 2.5vf²
vf² = 8

they both will have the same velocity
KE of block A= .5(4)(2.828²) = 16 J
KE of block B=.5(1)(2.828²) = 4 J</span>

5 0

4 years ago