/etc/services on my CentOS machine goes up to 49000. Reserved ports are less than 1024.
Well known and reserved ports are two different things. Well known ports only need a registration with IANA. Reserved ports, on *nixes, requires root for a deamon to bind to the port.
Answer:
See Explanation Below
Explanation:
The new code segment is
int feb = 28;
if ((year % 4) == 0 && (year % 100) != 0) // assume that year is an integer with a valid year value
{
System.out.println("This is a leap year");
feb = 29;
}
Assume year = 2020, the assigned value of feb is 29;
Reason below;
At line 2 of the new code segment, two conditions are tested both of which must be satisfied.
1. year % 4 == 0
2020 % 4 = 0
0 = 0 (True)
2. year % 100 != 0
2020 % 100 != 0
20 != 0 (True)
Since both conditions are true, the value assigned to feb will be 29 and
"This is a leap year" will be printed without the quotes
Answer:
true.
Explanation:
According to my research on information technology, I can say that based on the information provided within the question the statement is completely true. Procedural programming is a widely used paradigm that basically gives the program a set of routines or specifications, and the program mixes and matches them as they continuously repeat the process. It is used in many areas, including video game development.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
1. true
2.false
3.true
4. many - I'm not too certain of this answer
5. track changes
