All categories

4 years ago

Slope is 5, and (2,6) is on the line

Mathematics

1 answer:

tigry1 [53]4 years ago

3 0

Y - 6= 5(x - 2)

y - 6 = 5x - 10
y= 5x - 4

You might be interested in

For -180°<θ<0 , which of the primary trigonometric functions may have positive values?

Jobisdone [24]

Answer:

cos theta = adj / hyp is positive (+/+)

Step-by-step explanation:

In this open interval, the hypotenuse (radius) is always positive, whereas the adjacent side is positive and the opposite side negative.

in this interval:

sin theta = opp / hyp is neg (-/+)

cos theta = adj / hyp is positive (+/+)

tan theta = opp / adj = (-/+) : negative

6 0

3 years ago

(QUICKLY!) Describe two methods that can be used to find the area of the composite figure.

ryzh [129]

Answer:4 squares or a rectangle and a square

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Dina invests $600 for 5 years at a rate of 2% per year compound interest.

kenny6666 [7]

Answer:

The investment after 5 years is $ 662.45.

Step-by-step explanation:

Principal, P = $ 600

Time, t = 5 years

Rate of interest, R = 2 %

Time , t = 5 years

The amount after the time 5 years is

$A = P \times \left ( 1+\frac{R}{100} \right )^t\\\\A = 600\left ( 1+0.02 \right )^5\\\\A = 662.45$

So, the investment after 5 years is $ 662.45.

4 0

3 years ago

In this exercise, we estimate the rate at which the total personal income is rising in the Richmond-Petersburg, Virginia, metrop

babymother [125]

Answer:

The rate at which the total income is increasing is$1627415600

Step-by-step explanation:

From the given data

Population in the area=P=961400

The rate of increase in population=dP/dt=9200

The Average Income=I=$30593

The rate of increase in Average Income=dI/dt=$1400

Now the total income is given as

Total Income=TI=PI

So the rate of increase of total personal income is given as $\frac{d}{dt}(PI)$

From the product rule of derivatives

$\frac{d}{dt}(P*I)=I*\frac{dP}{dt}+P*\frac{dI}{dt}$

Here

I is the Average Income which is given as $30593

dI/dt is the rate of increase of income which is given as $1400.

P is the population of the area which is given as 961400

dP/dt=9200 is the rate of increase of population which is given as 9200

By substituting the values,

$\frac{d}{dt}(P*I)=I*\frac{dP}{dt}+P*\frac{dI}{dt}\\\frac{d}{dt}(P*I)=30593*9200+961400*1400\\\frac{d}{dt}(P*I)=\$1627415600$

So the rate at which the total income is increasing is$1627415600

8 0

4 years ago

Change 68/11 into a mixed number.

SpyIntel [72]

$\dfrac{68}{11}=\dfrac{66+2}{11}=\dfrac{66}{11}+\dfrac{2}{11}=6+\dfrac{2}{11}$

6 0

4 years ago