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ella [17]
3 years ago
5

What is the median of this graph?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0
5+4+3+2+1+0=14

14/4=3
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Factorise 2x squared +6x
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Is the line through points P(–3, –2) and Q(2, 3) perpendicular to the line through points R(10, –1) and S(15, –6)? Explain.
Alexus [3.1K]

Answer:

B. Yes. Their slopes have product -1.

Step-by-step explanation:

Given:

Line passing through P(-3, -2) and Q(2, 3)

Line passing through R(10, -1) and S(15, -6)

Required:

To determine if both lines are perpendicular.

SOLUTION:

Two lines are considered perpendicular if the product of their slopes equal -1.

To determine if both lines given in the question are perpendicular, first, calculate their slope using: m = \frac{y_2 - y_1}{x_2 - x_1}

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Let,

P(-3, -2) = (x_1, y_1)

Q(2, 3) = (x_2, y_2)

m = \frac{3 -(-2)}{2 -(-3)}

m = \frac{5}{5} = 1

Slope of line passing through R(10, -1) and S(15, -6):

Let,

R(10, -1) = (x_1, y_1)

S(15, -6) = (x_2, y_2)

m = \frac{-6 -(-1)}{15 - 10}

m = \frac{-5}{5} = -1

The product of their slopes = 1 × -1 = -1

<u><em>Therefore, the lines are perpendicular.</em></u>

The answer is: <em><u>B. "Yes. Their slopes have product -1."</u></em>

5 0
3 years ago
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