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Leona [35]
2 years ago
8

The math club is baking pies for a bake sale the fruit pie recipe calls for twice as many peaches as nectarines if it takes a to

tal of 168 pieces of fruit for all the pies,how many nectarines are needed?
Mathematics
1 answer:
xxMikexx [17]2 years ago
4 0

Answer:112 nectarines are needed.

Step-by-step explanation:

The math club is baking pies for a bake sale and they would require a number of peaches and nectarines

Let x represent the number of peaches.

Let y represent the number of peaches.

The fruit pie recipe calls for twice as many peaches as nectarines. This is expressed as

y = 2x

if it takes a total of 168 pieces of fruit for all the pies, it means that

x + y = 168 - - -- - - - - - 1

Substituting y = 2x into equation 1, it becomes

x + 2x = 168

3x = 168

x = 168/3 = 56

y = 2x

y = 2×56 = 112

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Ostrovityanka [42]
The solution is the point of intersection between the two equations.

Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.

In the graph the first equation is in blue and the second in red.

The point of intersection = the solution = (-6 , -1)



If you dont have access to a graphing calculator you could draw the graphs by hand;

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2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph

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Step-by-step explanation:

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