Answer:
(5, 4 )
Step-by-step explanation:
Given the 2 equations
3x - y = 11 → (1)
- 2x - 4y = - 26 → (2)
Multiplying (1) by - 4 and adding to (2) will eliminate the y- term
- 12x + 4y = - 44 → (3)
Add (2) and (3) term by term to eliminate y
- 14x + 0 = - 70
- 14x = - 70 ( divide both sides by - 14 )
x = 5
Substitute x = 5 into either of the 2 equations and solve for y
Substituting into (1)
3(5) - y = 11
15 - y = 11 ( subtract 15 from both sides )
- y = - 4 ( multiply both sides by - 1 )
y = 4
solution is (5, 4 )
Answer:
y=25*2ˣ.
Step-by-step explanation:
no details.
Complete question :
Cheddar Cheese
$3/lb
Swiss Cheese
$5/lb
Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Answer:
10 lbs of cheddar cheese
6 lbs of Swiss cheese
$3a + $5b = $30
Step-by-step explanation:
Given that :
Cheddar cheese = $3/lb
Swiss cheese = $5/lb
Total amount budgeted for cheese = $30
How many pounds of cheese can Keisha get if she buys only Cheddar cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of cheddar cheese
$30 / 3 = 10 pounds of cheedar cheese
Only Swiss cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of Swiss cheese
$30 / 5 = 6 pounds of Swiss cheese
A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Let amount of cheddar cheese she can get = a
Let amount of Swiss cheese she can get = b
Hence,
(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount
(3 * a) + (5 * b) = $30
$3a + $5b = $30
The answer to this question is y=5
