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Cloud [144]
3 years ago
15

What is the distance between the points (7, −10) and (−8, −10)?

Mathematics
2 answers:
marin [14]3 years ago
7 0

Answer:

15

Step-by-step explanation:

Using the distance formula

Ganezh [65]3 years ago
4 0

Answer:

15

hope this helps please make mine the brainliest

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The set of integers is not closed for
Brilliant_brown [7]
Hello,

N is closed for an opération(µ)  means that
a,b ∈ N : a µ b ∈N (i suppose so)

Answer (1) ex 2/3 ∉ N

Answer (4) ex 2-3 ∉ N

∀ a,b ∈ N: a+b ∈N is true ; not a answer.

∀ a,b ∈ N: a*b ∈N is true ; not a answer.


 


4 0
3 years ago
3(x-6) + 4 + 5x - 6<br><br> (use distributive property)<br><br> please help asap!
Dmitry_Shevchenko [17]

Answer:

8x - 20

Step-by-step explanation:

3(x - 6) + 4 + 5x - 6         \longmapsto       Distribute 3 to (x - 6)

3(x) - 3(6) + 4 + 5x - 6

3x - 18 + 4 + 5x - 6

Simplify:

3x + 5x - 18 + 4 - 6

8x -18 - 2

8x - 20

-Chetan K

3 0
2 years ago
Read 2 more answers
Jeff Wilke says that one of the most important things an experimenter should do when setting up a hypothesis test is write down
Hitman42 [59]

Answer:

Please see attachment for co troll and treatment for amazon

8 0
3 years ago
Apply The Remainder Theorem, Fundamental Theorem, Rational Root Theorem, Descartes Rule, and Factor Theorem to find the remainde
Over [174]

9514 1404 393

Answer:

  possible rational roots: ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12}

  actual roots: -1, (2 ±4i√2)/3

  no turning points; no local extrema

  end behavior is same-sign as x-value end-behavior

Step-by-step explanation:

The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.

The Rational Root Theorem tells us any rational roots will be of the form ...

  ±{factor of 12}/{factor of 3} = ±{1, 2, 3, 4, 6, 12}/{1, 3}

  = ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12} . . . possible rational roots

Descartes' Rule of Signs tells us the two sign changes mean there will be 0 or 2 positive real roots. Changing signs on the odd-degree terms makes the sign-change count go to 1, so we know there is one negative real root.

The y-intercept is 12. The sum of all coefficients is 22, so f(1) > f(0) and there are no positive real roots in the interval [0, 1]. Synthetic division by x-1 shows the remainder is 22 (which we knew) and all the quotient coefficients are all positive. This means x=0 is an upper bound on the real roots.

The sum of odd-degree coefficients is 3+8=11, equal to the sum of even-degree coefficients, -1+12=11. This means that -1 is a real root. Synthetic division by x+1 shows the remainder is zero (which we knew) and the quotient coefficients alternate signs. This means x=-1 is a lower bound on real roots. The quotient of 3x^2 -4x +12 is a quadratic factor of f(x):

  f(x) = (x +1)(3x^2 -4x +12)

The complex roots of the quadratic can be found using the quadratic formula:

  x = (-(-4) ±√((-4)^2 -4(3)(12)))/(2(3)) = (4 ± √-128)/6

  x = (2 ± 4i√2)/3 . . . . complex roots

__

The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.

4 0
3 years ago
A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the
Nookie1986 [14]
X the first account  interest = x/100*2 = 2x/100 
(x + 800)/100 * 4 =( 4x + 3200)/100 
2x/100 + (4x + 3200)/100 = 92
2x + 4x + 3200 = 9200 
6x = 6000
x = 1000
C is the answer
3 0
3 years ago
Read 2 more answers
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