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strojnjashka [21]
3 years ago
8

What is the positive solution of x2 – 36 = 5x?

Mathematics
2 answers:
N76 [4]3 years ago
8 0

Answer:the answer is 9

Step-by-step explanation:

jeka57 [31]3 years ago
3 0
<span>First, set this equation equal to 0 by getting 5x over to the other side by subtracting it both sides.</span>
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P-6= -5 can u slove this equation plx
torisob [31]
So u have to solve for p to do that you must isolate p by moving -6 after the equal sign -5+6=1 and there is the answer: 1 hope this helps!!

5 0
3 years ago
Table 2
astra-53 [7]
The answer is 3rd one
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How many times larger is 6x10^3 than 2x10^2
Alecsey [184]
30 times greater I hope it helps unlike that other answer...
7 0
3 years ago
HELP ASAP ...........
dedylja [7]

Answer:

A

Step-by-step explanation:

Given

y - 2x - 8 = 0 ( add 2x + 8 to both sides )

y = 2x + 8 → (1)

y² + 8x = 0 → (2)

Substitute y = 2x + 8 into (2)

(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify

4x² + 32x + 64 + 8x = 0

4x² + 40x + 64 = 0 ( divide through by 4 )

x² + 10x + 16 = 0 ← in standard form

(x + 8)(x + 2) = 0 ← in factored form

x + 8 = 0 ⇒ x = - 8

x + 2 = 0 ⇒ x = - 2

Substitute these values into (1) for corresponding values of y

x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)

x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )

Calculate the length of PQ using the distance formula

PQ = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )

PQ = \sqrt{(-2-(-8))^2+(4-(-8))^2}

      = \sqrt{(-2+8)^2+(4+8)^2}

       = \sqrt{6^2+12^2}

       = \sqrt{36+144}

       = \sqrt{180}

       = \sqrt{36(5)}

       = \sqrt{36} × \sqrt{5}

        = 6\sqrt{5} → A

8 0
2 years ago
Helppppppppppppppppp
shepuryov [24]
( im not really sure) i think it would be a, sorry if im wrong!
3 0
3 years ago
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