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Tems11 [23]
3 years ago
7

PLEASE HELP FAST FOR 20p

Physics
1 answer:
aliya0001 [1]3 years ago
8 0

equivalent force was applied

       N    

W              E

        S

because its is being pulled by south and west it will travel south west.

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A jogger runs the first 1000 meters of a race in 250 seconds. What is the joggers speed
Andrei [34K]
4 meters per second. hope this helped
7 0
4 years ago
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Planet X has three times the free-fall acceleration of Earth.
serious [3.7K]

Answer:

a) The ball goes one-third times higher on X

b) The ball goes three times higher on X.

Explanation:

a)

  • As the initial velocity is the same than on Earth, but the free-fall acceleration is three times larger, this means that the only net force acting on the ball (gravity) will be three times larger, so it is clear that the ball will reach to a lower height, as it will slowed down more quickly.
  • Kinematically, as we know that the speed becomes zero when the ball reaches to the maximum height, we can use the following kinematic equation:

        v_{f} ^{2} - v_{o}^{2}  = 2* \Delta h* g

       since vf = 0, solving for Δh, we have:

       \Delta h = h_{max} =\frac{v_{o} ^{2}}{2*g} (1)

       if v₀ₓ = v₀E, and gₓ = 3*gE, replacing in (1), we get:

     Δhₓ = 1/3 * ΔhE

      which confirms our intuitive reasoning.

b)    

  • Now, if the initial velocity is three times larger than the one on Earth, even the acceleration due to gravity is three times larger, we conclude that the ball will go higher than on Earth.
  • We can use the same kinematic equation as in (1) replacing Vox by 3*VoE, as follows:

       \Delta h = h_{max} =\frac{(3*v_{o}) ^{2}}{2*3*g} (2)

      Replacing the right side of (1) in (2), we get:

      Δhx = 3* ΔhE

      which confirms our intuitive reasoning also.

7 0
3 years ago
Compare the weight of a mountain climber when she is at the bottom of a mountain with her weight when she is at the top of the m
kakasveta [241]

Answer:

The correct answer is  a. Both are the same

Explanation:

For this calculation we must use the gravitational attraction equation

    F = G m M / r²

Where M will use the mass of the Earth, m the mass of the girl and r is the distance of the girl to the center of the earth that we consider spherical

To better visualize things, let's repair the equation a little

     F = m (G M / r²)

The amount in parentheses called acceleration of gravity, entered the force called peos

     g = G M / r²

     F = W

    W = m g

When analyzing this equation we see that the variation in the weight of the girl depends on the distance, which is the radius of the earth plus the height where the girl is

    r = Re + h

    Re = 6.37 10⁶ m

    r² = (Re + h)²

    r² = Re² (1 + h / Re)²

Let's replace

    W = m (GM / Re²)   (1+ h / Re)⁻²

    W = m g   (1+ h / Re)⁻²

This is the exact expression for weight change with height, but let's look at its values ​​for some reasonable heights h = 6300 m (very high mountain)

     h / Re = 10 ⁻³

     (1+ h / Re)⁻² = 0.999⁻²

Therefore, the negligible weight reduction, therefore, for practical purposes the weight does not change with the height of the mountain on Earth

The correct answer is a

4 0
3 years ago
Can someone plz help me.
Scilla [17]

Answer:

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6 0
3 years ago
Read 2 more answers
A train has a constant velocity of 2 m/s east. What is the magnitude of the horizontal acceleration of the train? A. −2 m/s² B.
Serga [27]

"Acceleration" is the rate at which velocity changes.
So "constant velocity" is a very good definition of "no acceleration".

Choice-B is the correct one.
5 0
3 years ago
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