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3 years ago

Answer the questions below correctly (please) and I'll give brainliest!

Physics

1 answer:

gregori [183]3 years ago

8 0

Answer:

The difference between the greenhouse effect and global warming is that the greenhouse effect is when the sun’s energy reaches the earth’s atmosphere and some of it is reflected back to space and the rest is absorbed and re-radiated by greenhouse gases. Global warming is the unusually rapid increase in Earth’s average surface temperature. The difference is that that the green house effect is a natural process that happens constantly and global warming is a change due to earth’s climate causing it to heat up. Carbon monoxide affects global warming by trapping the gasses in the atmosphere which causes an increase in temperature. For an example, three sources of atmospheric carbon dioxide is car fumes, factory fumes, and coal.

Explanation:

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A person on a daily diet of 2,500 calories should get no_more than calories from fat each day.

ivann1987 [24]

Answer:

35%

Explanation:

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Before starting the simulation and having the waves encounter the barrier, the wavelength is manipulated. This is the (1. BLANK)

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Which are uses of electromagnetic waves? Check all that apply.

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The first, third, fourth, fifth and sixth

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4 years ago

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Be sure to answer all parts. Without stratospheric ozone (O3), harmful solar radiation would cause gene alterations. Ozone forms

Ratling [72]

Answer:

for C-Cl bond $\lambda_1=3.66\times 10^{-9}\ m$

for O-O bond $\lambda_2=2.43\times 10^{-9}\ m$

Explanation:

We have the bond enegy for C-Cl, $BE_1=327\ kJ.mol^{-1}= 327000\times 1.66\times 10^{-22}\ J\ per\ molecule$

bond enegy for C-Cl, $BE_2=494\ kJ.mol^{-1}= 494000\times 1.66\times 10^{-22}\ J\ per\ molecule$

Now as we know the energy of electromagnetic waves is given by:

$E=h.\nu$

here E = BE

Then for C-Cl:

$327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1$

$\nu_1=8.18733\times 10^{16}\ Hz$

Now wavelength:

$\lambda_1=\frac{c}{\nu_1}$

$\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}$

$\lambda_1=3.66\times 10^{-9}\ m$

For O2:

$494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2$

$\nu_2=1.236863\times 10^{17}\ Hz$

Now wavelength:

$\lambda_2=\frac{c}{\nu_2}$

$\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}$

$\lambda_2=2.43\times 10^{-9}\ m$

8 0

3 years ago

Two carts, one twice as heavy as the other, are at rest on a horizontal track. A person pushes each cart for 8 s. Ignoring frict

GalinKa [24]

Answer:

The correct option is: B that is 1/2 K

Explanation:

Given:

Two carts of different masses, same force were applied for same duration of time.

Mass of the lighter cart = $m$

Mass of the heavier cart = $2m$

We have to find the relationship between their kinetic energy:

Let the KE of cart having mass m be "K".

and KE of cart having mass m be "K1".

As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.

Numerical analysis.

⇒ $KE = \frac{mv^2}{2}$

⇒ $KE = \frac{mv^2}{2}\times \frac{m}{m}$

⇒ $KE = \frac{m^2v^2}{2}\times \frac{1}{m}$

⇒ $KE = \frac{(mv)^2}{2}\times \frac{1}{m}$

⇒ $KE = \frac{(\triangle p)^2}{2}\times \frac{1}{m}$

⇒ $KE = \frac{(\triangle p)^2}{2m}=\frac{(F\times t)^2}{2m}$

Now,

Kinetic energies and their ratios in terms of momentum or impulse.

KE (K) of mass m.

⇒ $K=\frac{(F\times t)^2}{2m}$ ...equation (i)

KE (K1) of mass 2m.

⇒ $K_1=\frac{(F\times t)^2}{2\times 2m}$

⇒ $K_1=\frac{(F\times t)^2}{4m}$ ...equation (ii)

Lets divide K1 and K to find the relationship between the two carts's KE.

⇒ $\frac{K_1}{K} =\frac{(F\times t)^2}{4m} \times \frac{2m}{(F\times t)^2}$

⇒ $\frac{K_1}{K} =\frac{2m}{4m}$

⇒ $\frac{K_1}{K} =\frac{2}{4}$

⇒ $\frac{K_1}{K} =\frac{1}{2}$

⇒ $K_1=\frac{K}{2}$

⇒ $K_1=\frac{1}{2}K$

The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.

7 0

3 years ago