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3 years ago

Answer the questions below correctly (please) and I'll give brainliest!

Physics

1 answer:

gregori [183]3 years ago

8 0

Answer:

The difference between the greenhouse effect and global warming is that the greenhouse effect is when the sun’s energy reaches the earth’s atmosphere and some of it is reflected back to space and the rest is absorbed and re-radiated by greenhouse gases. Global warming is the unusually rapid increase in Earth’s average surface temperature. The difference is that that the green house effect is a natural process that happens constantly and global warming is a change due to earth’s climate causing it to heat up. Carbon monoxide affects global warming by trapping the gasses in the atmosphere which causes an increase in temperature. For an example, three sources of atmospheric carbon dioxide is car fumes, factory fumes, and coal.

Explanation:

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Two identical blocks are heated to different temperatures. The blocks are placed so that they touch, and heat begins to flow bet

baherus [9]

The pair of blocks is insulated, so no energy escapes. The pair of temperatures possible is 95 +95 temperature blocks.

<h3>What is thermal equilibrium?</h3>

When two objects are in direct contact and transfer heat through conduction. When the both object attain same temperature after sometime, they are called in thermal equilibrium.

Two identical blocks are heated to different temperatures. The blocks are placed so that they touch, and heat begins to flow between blocks. The heat will continue to until and unless they have same temperatures. After they being isolated, the temperature of both will be same and no heat is transferred outside.

Thus, the pair of temperatures possible is 95 +95 temperature blocks.

Learn more about temperature.

brainly.com/question/11464844

#SPJ1

4 0

2 years ago

A projectile has an initial horizontal velocity of 15 meters per second and an initial vertical velocity of 25 meters per second

Artyom0805 [142]

Answer:

75 m

Explanation:

The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.

The horizontal component of the velocity of the projectile is

$v_x = 15 m/s$

and it is constant during the motion;

the total time of flight is

t = 5 s

Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:

$d= v_x t =(15 m/s)(5 s)=75 m$

5 0

3 years ago

The top of lake is frozen as atmospheric temperature is -10 degree Celsius the temperature of the bottom of the lake is most lik

hjlf

4°Celcius Water is densest at 4°C

4 0

3 years ago

what is one example of the use of an infrared sensor? Track shipments, monitor building exit and entry, water flows without turn

kap26 [50]

<span>Your answer should be water flows without turning on a facet. Hope this helps!
</span>

6 0

3 years ago

Read 2 more answers

A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its

Pavel [41]

Answer:

$v_2 = 5.6 \ m/s$

$P_2 = 80600 \ Pa$

Explanation:

From the question we are told that

The pressure of the water in the pipe is $P_1= 110 \ kPa = 110 *10^{3 } \ Pa$

The speed of the water is $v_1 = 1.4 \ m/s$

The original area of the pipe is $A_1 = \pi \frac{d^2 }{4}$

The new area of the pipe is $A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}$

Generally the continuity equation is mathematically represented as

$A_1 * v_1 = A_2 * v_2$

Here $v_2$ is the new velocity

$\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2$

=> $\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2$

=> $d^2 * 1.4 = \frac{d^2}{4} * v_2$

=> $1.4 = 0.25 * v_2$

=> $v_2 = 5.6 \ m/s$

Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the Bernoulli's equation for constant height to calculate the pressure

This is mathematically represented as

$P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2$

Here $\rho$ is the density of water with value $\rho = 1000 \ kg /m^3$

$P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ]$

=> $P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ]$

=> $P_2 = 80600 \ Pa$

4 0

3 years ago