All categories

3 years ago

A jogger runs the first 1000 meters of a race in 250 seconds. What is the joggers speed

Physics

2 answers:

Lelu [443]3 years ago

8 0

Answer:

The speed of the joggers is 4 m/s.

Explanation:

Given that,

Distance covered by the joggers, d = 1000 meters

Time taken by the joggers, t = 250 seconds

We need to find the joggers speed. It is given by :

$v=\dfrac{d}{t}$

$v=\dfrac{1000\ m}{250\ s}$

v = 4 m/s

So, the joggers speed is 4 m/s. Hence, this is the required solution.

Andrei [34K]3 years ago

7 0

4 meters per second. hope this helped

You might be interested in

Which of the following statements is/are true? Check all that apply. Check all that apply. The total mechanical energy of a syst

Taya2010 [7]

Answer:

1) True, 2) True, 3) False, 4) False, 5) False

Explanation:

1) True. Dissipative energy cannot be recovered, in general it is a form of heat

2) True. The dissipation can be by radiation, heat

3) False. Mechanical energy is divided into K and U but not in equal parts

4) False. When there are dissipative interactions, part of the mechanical energy is set in the form of heat, so its value decreases

5) False. Mechanical energy is the sum of those two energies

8 0

3 years ago

A Ferris wheel is turning at a constant speed. The riders are _________________ accelerating.

aivan3 [116]

Answer:

The riders are <u>radially</u> accelerating.

Explanation:

The Ferris wheel is making a circular motion. If it is moving with constant velocity, than the acceleration is

$a_{rad} = \frac{v^2}{R}$

towards the center of the wheel.

So, the riders are subject to a constant and radial acceleration, which is called the centripetal acceleration.

3 0

3 years ago

A 0.140-kg baseball is dropped from rest from a height of 1.8 m above the ground. It rebounds to a height of 1.4 m. What change

aliina [53]

Answer:

$\Delta p=-1.56\ kg-m/s$

Explanation:

It is given that,

Mass of the baseball, m = 0.14 kg

It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :

$u=\sqrt{2gh}$

h = 1.8 m

$u=\sqrt{2\times 9.8\times 1.8}$

u = 5.93 m/s

Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :

$v=\sqrt{2gh'}$

h' = 1.4 m

$v=-\sqrt{2\times 9.8\times 1.4}$

v = -5.23 m/s

The change in the momentum of the ball is given by :

$\Delta p=m(v-u)$

$\Delta p=0.14(-5.23-5.93)$

$\Delta p=-1.56\ kg-m/s$

So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.

4 0

4 years ago

Describe how cell membranes are selectively permeable

attashe74 [19]

<span>Cell membranes are selectively permeable because it allows some things to enter or leave the cell while keeping other things outside or inside the cell.</span>

5 0

3 years ago

A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial speed of 32 m/s, what is its new speed?

Nata [24]

B should be the answer

Look at this example to help you

7 0

4 years ago