Explanation:
ans ...(5,3)..............
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Answer:
a) 2.4 mm
b) 1.2 mm
c) 1.2 mm
Explanation:
To find the widths of the maxima you use the diffraction condition for destructive interference, given by the following formula:
a: width of the slit
λ: wavelength
m: order of the minimum
for little angles you have:
y: height of the mth minimum
a) the width of the central maximum is 2*y for m=1:
b) the width of first maximum is y2-y1:
c) and for the second maximum:
The correct answer is: electrons/second
Explanation:
5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:
Electrons per second =