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Snezhnost [94]
3 years ago
5

Cheyenne needs to write a linear equation that is parallel to the x-axis. Which equation could she write?

Mathematics
1 answer:
barxatty [35]3 years ago
4 0
Dog let me cut it to ya. Ain’t nobody gonna know that.
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What are the coordinates of the image produced by applying the composition ry o T0-3 to the point (3, 5)? A. (–3, 2) B. (–3, 8)
Gennadij [26K]

Answer:

C. (3,6)

explenation

We are given that,

The point (-3,-6) is transformed by the rule .

That is, the point is reflected across y-axis and then reflected across x-axis.

That is, the rule for the transformation is (x,y) → (-x,y) → (-x,-y).

So, we get,

(-3,-6) → (3,-6) → (3,6)

Thus, the co-ordinates of the image are (3,6).

So, option C is correct.

3 0
3 years ago
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Write each equation in standard form.<br> y - 10 = 2(x - 8)<br> How do I solve this
fredd [130]

First, we can expand the terms on the right side of the equation:

y

−

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2

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x

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y

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−

(

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y

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16

Next, we can add

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y

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0

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0

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6

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Now, multiply each side of the equation by

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+

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y

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6

2

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+

(

−

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or

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4 0
3 years ago
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Write 0.001 as a fraction
svlad2 [7]

Answer: 1/1000


Step-by-step explanation:


7 0
3 years ago
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Find the error &amp; find the correct answer 2In(x)=In(3x)-[In(9)-2In(3)] In(x^2)=In(3x)-[In(9)-In(9)] In(x^2)=In(3x)-0 In(x^2)=
Art [367]

Answer:

Error:lnx^2=ln 3x not ln\frac{3x}{0}

Solution:x=0 and 3

Step-by-step explanation:

We have to find the error and correct answer

Given:2ln x=ln(3x)-[ln9-2ln(3)]

lnx^2=ln(3x)-[ln9-ln3^2]

Using the formula

alog b=logb^a

lnx^2=ln(3x)-[ln9-ln9]

lnx^2=ln(3x)-0

lnx^2=ln(3x)

x^2=3x

x^2-3x=0

x(x-3)=0

Therefore, x=0 and x=3

But last step in the given solution

lnx^2=ln\frac{3x}{0}=\infty

It is wrong this property is used when

log m-log n then

log\frac{m}{n}

Hence, the student wrote  lnx^2=ln\frac{3x}{0}instead of lnx^2=ln3x and solution is given by

x=0 and x=3

4 0
3 years ago
Find the volume of the prism shown.
nlexa [21]

Answer:

Volume of a pyramid is

V=lwh÷3

=(4·5·6)÷3

=40

6 0
3 years ago
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