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3 years ago

Me ajuda ai ....10x-1=2x^2+7

Mathematics

1 answer:

garik1379 [7]3 years ago

3 0

Answer:

x = 1 and/or x = 4

Step-by-step explanation:

You can solve by factoring, using the quadratic formula, or completing the square.

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write a equation in a point-slope form fir the line through the given point with the given slope (9,-1);m=4/3

gavmur [86]

Answer:

y +1 = 4/3( x-9)

Step-by-step explanation:

Point slope form of an equation is

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on a line

y - -1 = 4/3( x-9)

y +1 = 4/3( x-9)

6 0

3 years ago

Sebastian buys a gift which costs £18.20 He pays with a £20 note. (a) How much change does he receive?

Triss [41]

Answer:

1.80

Step-by-step explanation:

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5 0

2 years ago

Please help and thank you

Feliz [49]

Answer:

Step-by-step explanation:

6≤x<21

5 0

3 years ago

A rectangular vegetable patch is 93 feet long and 37 feet wide. What is its area?

stealth61 [152]

Answer:

A= 3441

P = 260

Step-by-step explanation:

Area = l x w

93 x 37 = =3441

Perimeter = 2l + 2w

2(93) + 2(37) = 260

5 0

3 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

3 years ago