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3 years ago

How do you solve problems algebraically? PLEASE HELP

Mathematics

1 answer:

Rudik [331]3 years ago

6 0

Step 1: Add the two equations.

Step 2: Solve for x.

Step 3: To find the y-value, substitute in 3 for x in one of the equations.

Step 4: Solve for y.

Step 5: Identify the solution as an ordered pair.

What if adding or subtracting does not eliminate a variable? Example. 3x – y = 8. x + 2y = 5.

MARK AS BRAINIEST PLEASE

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2m=p-q/r solve for r

Oduvanchick [21]

To solve for r, you would start by subtracting p from both sides.

2m - p = -q/r

Multiply everything by r.

2mr - pr = -q

Factor r out of the left side of the equation.

r(2m - p) = -q

Divide both sides by (2m - p).

r = $\frac{-q}{2m-p} = \frac{q}{2m + p}$ .

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3 years ago

Which equation will solve the following word problem? One small pitcher and one large pitcher can hold 12 cups of water. If the

Inessa [10]

Answer:

Option (1).

Step-by-step explanation:

Amount of water hold by both the pitchers (Large + small) = 12 cups

Let the small pitcher holds the water = S cups

If the water hold by the large pitcher is twice the size of the small pitcher, then the amount of water hold by large pitcher = 2S

Total amount water hold by both = S + 2S

Equation for this situation will be,

S + 2S = 12

Therefore, Option (1) will be the answer.

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3 years ago

The number of girls who work at Super shopper is 2 more than 3 times the number of boys. If 30 boys work at super shopper; how m

mote1985 [20]

I think its 92 but im not entirely sure. hope it helps though

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3 years ago

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Which number is not in scientific notation? Question 15 options: 1) 0.2 ⋅ 103 2) 3 ⋅ 1028 3) 1.03 ⋅ 10−2 4) 1.5 ⋅ 10−6

SashulF [63]

I believe it’s number 2.

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3 years ago

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At the start of the month, the value of an investment was $73.42. By the end of the month, the value of the investment changed b

Aleonysh [2.5K]

Answer:

0.8%.

Step-by-step explanation:

Given:

At the start of the month, the value of an investment was $73.42.

By the end of the month, the value of the investment changed by a loss of $13.53.

Question asked:

What was the value, in dollars, of the investment at the end of the month?

What was the percent loss?

Solution:

At the start of the month, the value of an investment = $73.42.

Loss = $13.53.

<u><em>The value, of the investment at the end of the month = The value of an investment at the start of the month - loss</em></u>

The value, of the investment at the end of the month = $73.42 - $13.53

= $59.89

Thus, the value, of the investment at the end of the month is $59.89.

Now, we will find percent loss:-

$Percent\ loss = \frac{Loss}{value\ of \ investment\ at \ start}$

$=\frac{59.89}{73.42} \\=0.81\%$

Thus, percent loss on investment by the end of the month is 0.8%.

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3 years ago