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Mrrafil [7]
3 years ago
13

How do you solve problems algebraically? PLEASE HELP

Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Step 1: Add the two equations.

Step 2: Solve for x.

Step 3: To find the y-value, substitute in 3 for x in one of the equations.

Step 4: Solve for y.

Step 5: Identify the solution as an ordered pair.

What if adding or subtracting does not eliminate a variable? Example. 3x – y = 8. x + 2y = 5.

MARK AS BRAINIEST PLEASE

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PLEASE HELP ME NOW URGENT
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ANSWER

y   = 3 \pm \sqrt{21}

EXPLANATION

The quadratic equation is:

{y}^{2}  - 6y - 12 = 0

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Add the square of half, the coefficient of y to both sides.

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y = 3 \pm \sqrt{21}

The first choice is correct.

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