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4 years ago

At the theatre one section of seats 8 rows with 12 seats in each row

Mathematics

2 answers:

Bingel [31]4 years ago

5 0

12 seats in 8 rows equals 96 seats total.

Please mark brainliest answer, I need one more <3

Paul [167]4 years ago

3 0

12 times 8 equals 96

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-1/2 w -3/5= 1/5w W=

Vinil7 [7]

The exact form is: w = -6/7

8 0

3 years ago

Find the missing side. Round to the nearest tenth. Х 28° 15 x = [?]

Effectus [21]

Given:

The right triangle with base 15 and hypotenuse x.

The measure of angle between base and hypotenuse is 28 degrees.

To find:

The value of x.

Solution:

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

In the given triangle,

$\cos 28^\circ=\dfrac{15}{x}$

$x=\dfrac{15}{\cos 28^\circ}$

$x=\dfrac{15}{0.8829476}$

$x=16.98855$

Round the value to the nearest tenth.

$x\approx 17.0$

Therefore, the value of x is 17.0 units.

8 0

3 years ago

PLEASE HELP!!!!!!

slava [35]

9514 1404 393

Answer:

A: (3x +4)

B: (4x +5y) × (4x -5y)

Step-by-step explanation:

Part A:

Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.

9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²

The side of the square is 3x+4.

Part B:

The difference of squares is factored like this:

a²-b² = (a +b)(a -b)

The given area expression is the difference of squares with ...

a = 4x, b = 5y

so, the factorization is ...

16x² -25y² = (4x +5y)(4x -5y)

The dimensions of the rectangle are (4x+5y) by (4x-5y).

3 0

3 years ago

If p is true and q is false, what is the truth value of p and q? a. true b. false c. 0 d. 1

Dovator [93]

Answer:

i think it will be 0 .....

8 0

3 years ago

Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50

steposvetlana [31]

Answer-

$f(2)= 6x^4-10x^3+40x-50=46$

Solution-

The given function is,

$\Rightarrow f(x)= 6x^4-10x^3+40x-50$

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

$\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= 96-80+80-50$

$\Rightarrow f(2)= 96-50$

$\Rightarrow f(2)= 46$

Therefore, f(2) was found to be 46.

7 0

4 years ago